All categories

3 years ago

What is the doamin/rang equality for y=x-5

Mathematics

1 answer:

Paladinen [302]3 years ago

4 0

The domain/range for y=x-5 is 3

You might be interested in

A bag contains purple marbles and red marbles, 34 in total. The number of purple marbles is 2 more than 3 times the number of re

Irina-Kira [14]

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

Firstly, you have to make an expression in terms of x where x represent red marbles. Given that the question says purple marbles is 2 more than 3 times the number of red marbles. So the expression is :

Let red marbles = x,

$purple = 2 + 3x$

$red = x$

Next, given that the total marbles in the bag is 34 so you have to add both marbles together and solve the value of x :

$2 + 3x + x = 34$

$4x = 32$

$x = 32 \div 4$

$x = 8$

Lastly, you have to substitute the value of x into the expression of purple marbles :

Let x = 8,

$purpe = 2 + 3(8)$

$purple = 26$

7 0

3 years ago

Steven has 7/10 of an hour to water 3 1/2 lawns. If he spends the same amount of time on each lawn, what fraction of an hour doe

mezya [45]

I think amswer is 2 9/20

7 0

3 years ago

The rule for a line whose gradient is -4 and y-intercept = 8 is:

irina [24]

Answer:

The rule for a line whose gradient is -4 and y-intercept = 8 is

$y=-4x+8$

Step-by-step explanation:

Equation of line slope intercept form is

$y=mx+b$ ------------- (1)

Where m is slope or gradient and b is y-intercept

Here

$m=-4 \ \ \ and \ \ \ b=8$

Substituting values in equation (1)

$y=-4x+8$

5 0

3 years ago

Tell whether the ordered paid is a solution of the linear inequality (0, -1) 2x + 3y = -3

Anastasy [175]

Step-by-step explanation:

I think that question is not correct

3 0

3 years ago

Hey guys, real fast how is the derivative of 3xlnx = 3+ln(x^3)

Harman [31]

You will need to use product rule.
The product rule is:
$\frac{d}{dx}[f(x)g(x)] = f'(x)g(x)+f(x)g'(x)$

$\frac{d}{dx}( 3x \ln x) =( \frac{d}{dx}(3x) \cdot \ln x )+ (3x \cdot \frac{d}{dx}(\ln x))\\\\ = 3\ln x + 3x\cdot \frac{1}{x}\\\\=3 \ln x + 3$

This can also be written as (using the log rules):
$3 \ln x + 3 = \boxed{\ln(x^3) + 3}$

4 0

3 years ago