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Vedmedyk [2.9K]
3 years ago
10

Solve the inequality LaTeX: 5x-6\le2+\left(3x-4\right)5 x − 6 ≤ 2 + ( 3 x − 4 ). Express the solution as an inequality.

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

x ≤ 2

Step-by-step explanation:

Given the inequality :

5 x − 6 ≤ 2 + ( 3 x − 4 )

Open The bracket

5x - 6 ≤ 2 + 3x - 4

Collect like terms

5x - 3x ≤ 2 - 4 + 6

2x ≤ 4

Dibide both sides by 2

2x /2 ≤ 4/ 2

x ≤ 2

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qwelly [4]

26cm           10cm       11cm    

Step-by-step explanation:

3 0
3 years ago
How do I solve this by graphing?
Inessa05 [86]
0 = 5x+3
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6 0
3 years ago
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1. Segment AE is 7 inches and AH is 7^/3 inches. What is the length of EH? Round to the nearest tenth.
Orlov [11]

Answer:

1.) 9.9

2.) 15.6

Step-by-step explanation:

1.) Consider triangle AEH

AEH is a right angle triangle as ∠AEH = 90°

AH is the hypotenuse of the triangle.

Applying Pythagorean theorem

AE^{2} + EH^{2} = AH^{2}

substituting values as given in the question:

7^{2} +EH^{2}=(7\sqrt{3} )^{2}\\EH^{2}=(7\sqrt{3} )^{2}-7^{2} \\EH^{2}=98\\EH=\sqrt{98}\\EH=7\sqrt{2}

∴ EH≈9.9

2.) Consider triangle CDF

CDF is a right angle triangle as ∠CDF = 90°

CF is the hypotenuse of the triangle.

Applying Pythagorean theorem

CD^{2} + DF^{2} = CF^{2}

substituting values as given in the question:

11^{2} +DF^{2}=(11\sqrt{3} )^{2}\\DF^{2}=(11\sqrt{3} )^{2}-11^{2} \\DF^{2}=242\\DF=\sqrt{242}\\DF=11\sqrt{2}

∴ DF≈15.6

3 0
3 years ago
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Can someone please help me with this MATH question ill give free points PLUS brainliest!!!!
irina1246 [14]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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2 over 5 x= 10 solve for x show your work
Sphinxa [80]

\frac{2}{5}x= 10

We need to solve for x

To get x alone we need to remove the denominator 5

To remove denominator 5  we multiply by 5 on both sides

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2x = 50

2x means 2 times x

2 is multiplied with x. so to remove 2 we divide by 2

\frac{2x}{2}= \frac{50}{2}

So x= 25


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3 years ago
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