Let be:Speed of the wind: WSpeed of the plane in still air: P
Against the wind the plane flew:Distance: d=175 milesTime: ta=1 hour 10 minutesta=1 hour (10 minutes)*(1 hour/60 minutes)ta=1 hour + 1/6 hourta=(6+1)/6 hourta=7/6 hourSpeed against the wind: Sa=d/taSa=(175 miles) / (7/6 hour)Sa=175*(6/7) miles/hourSa=1,050/7 miles per hourSa=150 mph
(1) P-W=Sa(1) P-W=150
The return trip only took 50 minutesDistance: d=175 milesTime: tr=50 minutestr=(50 minutes)*(1 hour/60 minutes)tr=5/6 hour
Speed retur trip: Sr=d/trSr=(175 miles) / (5/6 hour)Sr=175*(6/5) miles/hourSr=1,050/5 miles per hourSr=210 mph
(2) P+W=Sr(2) P+W=210
We have a system of 2 equations and 2 unknows:(1) P-W=150(2) P+W=210
Adding the equations:P-W+P+W=150+2102P=360Solving for P:2P/2=360/2P=180
Replacing P by 180 in equation (2):(2) P+W=210180+W=210
Solving for W:180+W-180=210-180W=30
Answers:The speed of the plane in still air was 180 mphThe speed of the wind was 30 mph
Answer:
y+9=1/5(x+3)
Step-by-step explanation:
Point slope formula: y-y1=m(x-x1)
slope=m
m=1/5
-3=x1 -9=y1
y-(-9) =1/5(x-(-3))
simplify...
y+9=1/5(x+3)
hope this helps!! :)
Answer:
(-2, 4)
Step-by-step explanation:
~When reflecting a point of the x-axis, the x value (or first number inside the parenthesis) does not change.
The reason the x-value does not change is because you are reflecting over the x-axis, making the point go up or down. That will change the y-value but the x-value only changes if you move to the left or the right. In this case, you can see that the point's x-value is -2, so that will not change. It's current y-value however is -4. When reflecting over an axis, the number that is changing (in this case the y-value) will just be flipped from positive to negative, or vise versa. In this case, -4 will be reflected to be 4, making point C reflected over the x-axis (-2, 4).
Answer:
i hope this works. Feel better soon!
Step-by-step explanation:
1.SAS 2 AAS 3 SAS 4 NOT CONGRUENT 5 SSS 6 ASA
7. ∠BAC≅∠EDC given, BC ≅ CE GIVEN ∠ACB≅∠DCE VERTICAL ANGLES, ΔABC≅ΔDEC AAS
8. ∠PQR≅∠TSR GIVEN R IS MIDPOINT OF PT GIVEN PQ≅ST GIVEN ΔPQR≅ΔTSR HYPOTENUSE LEG THEORUM
9. AC BISECTS BCD GIVEN ∠ABD≅∠ADC GIVEN ∠ACB≅∠ADC BISECTED ANGLES AC≅AC REFLEXIVE PROPERTY OF CONGRUENCE ΔABC≅ΔADC ASA AB≅AC SAME SIDES OF CONGRUENT TRIANGLES
Answer:
D
Step-by-step explanation:
You have 4 chairs originally, added 2 and if you separate the tables you would get T=whatever the number is. i think
