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kupik [55]
4 years ago
9

Which of the following functions would best model the situation above?

Mathematics
2 answers:
amid [387]4 years ago
3 0
Usually bacteria expansion is modeled with exponential function.
Absolute value is not the correct answer since it models linear growth. 
Logarithmic is not the correct answer since it has an asymptote in the direction of the x axis. 
I will answer to this question "Polynomial" since it is likely to represent bacteria growth. 

Zanzabum4 years ago
3 0
We have a function that models the problem in the following way.
 N = a (b) ^ 8.
 Where,
 a = number of bacteria initially.
 b = growth of bacteria per hour.
 8 = eight hours.
 answer:
 d. polynomial

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4x+6 find find the value
Alex Ar [27]

Answer:

-1.5 or -6/4

Step-by-step explanation:

Im assuming the equation is 4x+6=0

1.) subtract the 6 from each side.

4x= -6

2.) you need to isolate the X, so divide the 4 from each side.

X= -6/4 or -1.5

7 0
3 years ago
Suppose a car going 65 mph is traveling north parallel to a train going 50 mph. Once the front of the car is as far north as the
scoray [572]

Answer:

0.75 Miles

Step-by-step explanation:

To find the answer we have to find the difference in the distance the train and car travelled

65/60 is 1.083333 which is miles per minute then multiplied by 3 is 3.25 mile gone in 3 minutes

For the train it is 50/60 which is 0.833333 and the times 3 is 2.5 miles in three minutes

3.25 miles minus 2.5 miles is 0.75 miles so that is how long the train is

6 0
3 years ago
Joe what's to build a fence for his dog Charlie he plans to surround the rectangle to the right with fence. How many feet will h
Aleksandr [31]
Joe wants to build a fence for his dog Charlie.
The lengths of the perimeter of the rectangle that he plans to surround with fence are as follows:

10 feet + 15 feet + 10 feet + 15 +feet.

The total perimeter area of a rectangle is worked out as follows:
10 + 15 + 10 + 15 = 50 
Therefore Joe needs 50 feet of fencing to totally surround the rectangle with fence. 
3 0
4 years ago
Beth is knitting mittens and gloves. Each pair must be processed on three machines. Each pair of mittens requires 2 minutes on M
anygoal [31]

Answer:

Two mittens and seven gloves  

Step-by-step explanation:

I presume you are asking how many mittens and how many gloves Beth should knit to produce the most profit.

Let x = the number of mittens and

Let y = the number of gloves

1. Summarize the information in a table

\begin{array}{cccc}&\textbf{Mittens}& \textbf{ Gloves} & \textbf{Minutes Available}\\\text{Machine A} & 2 & 4 & 32\\\text{Machine B} & 2 & 2 & 18\\\text{Machine C} & 4 & 1 & 24\\\text{Unit profit} & $8.00 & $10.00 & \\\end{array}

2. List the constraints

(a) Beth can't make a negative number of mittens, so

x ≥ 0.

(b) Neither can she make a negative number of gloves, so

y ≥ 0.

(c) The total number of minutes on Machine A cannot exceed 32, so

2x + 4y ≤ 32.

(d) The total number of minutes on Machine B cannot exceed 18, so

2x + 2y ≤ 18.

(e) The total number of minutes on Machine C cannot exceed 24, so

4x +   y ≤ 24.

3. Write an equation for the profit

P = 8.00x + 10.00y

4. Graph the constraints to identify the feasible region

See the figure below. The feasible region is the dark green area where all three regions overlap.

5. Determine the points of intersection between the constraints  

(i) Constraints (c) and (d)

\begin{array}{rcr}2x + 4y  & = & 32\\2x + 2y & = & 18\\2y & = & 14\\y & = & \mathbf{7}\\2x + 14 & = & 18\\2x & = &4\\x & = & \mathbf{2}\\\end{array}\\

The lines intersect at (2,7).

(ii) Constraints (c) and (e)

\begin{array}{rcl}2x + 4y  & = & 32\\4x + y & = & 24\\4x + 8y & = & 64\\7y & = & 40\\y & = & \mathbf{\dfrac{40}{7}}\\\\4x + \dfrac{40}{7} & = & 24\\\\4x & = &24 - \dfrac{40}{7}\\\\4x & = & \dfrac{128}{7}\\\\x & = & \mathbf{\dfrac{32}{7}}\\\\\end{array}\\

The lines intersect at (27/7,32/7).

(iii) Constraints (d) and (e)

\begin{array}{rcr}2x + 2y  & = & 18\\4x + y & = & 24\\4x + 4y & = & 36\\3y & = & 12\\y & = & \mathbf{4}\\4x +4 & = & 24\\4x & = &20\\x & = & \mathbf{5}\\\end{array}\\

The lines intersect at (5,4).

6. Determine the x- and y-intercepts of the feasible region

(i) x-intercept

\begin{array}{rcr}4x + y & = & 24\\4x + 0  & = & 24\\x & = & \mathbf{6}\\\end{array}

The x-intercept is at (6,0).

(ii) y-intercept

\begin{array}{rcr}2x + 4y & = &32\\2(0) + 4y & = &32\\4y & = & 32\\y & = & \mathbf{8}\\\end{array}

The y-intercept is at (0,8).

The five black dots are the vertices of the polygon that represents the feasible region.

7. Calculate the maximum profit

Calculate the profit at each of the vertices.

(i) At (0,0)

P = 8.00x + 10.00y = 8.00(0) + 10.00(0) = 0 + 0 = $0

(ii) At (2,7)

P =  8.00(2) + 10.00(7) = 16 + 70 = $86

(iii) At (5,4)

P =  8.00(5) + 10.00(4) = 40 + 40 = $80

(iv) At (6,0)

P =  8.00(6) + 10.00(0) = 48 + 0 = $48

The maximum profit occurs at (2,7)

Thus, Beth should knit two mittens and seven gloves.

 

7 0
4 years ago
What is 87 1/2 % of 540.72
Doss [256]

Answer:

6.18

Step-by-step explanation:

4 0
3 years ago
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