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ioda
3 years ago
12

Remind write the equation of the line y=1/3(x+2). He solved for x and got x=3y-2. which of the following is a equivalent equatio

n for x?
Mathematics
1 answer:
jekas [21]3 years ago
3 0

Answer:

Step-by-step explanation:

multiply 1/3 by x and 3

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Write as a polynomial: <br><br> 2a^2(a-1)(3-a)
seropon [69]

Answer:

-2a^4+8a^3-6a^2

Step-by-step explanation:

2a^2(a-1)(3-a)

2a^2(-a^2 +3a-3+a)

2a^2(-a^2+4a-3)

-2a^4+8a^3-6a^2

6 0
2 years ago
A local magazine sells space for ads. It charges advertisers according to the fraction of a page purchased. Advertisers purchase
Novay_Z [31]

Answer:

3/16 of page 20

Step-by-step explanation:

1/8 = 2/16

2/16 + 1/16 = 3/16

6 0
3 years ago
Dwayne misses 12% of his foul shots and Bryan misses 0.2 of his foul shots. Write 12% and 0.2 as fractions in simplest form. The
Georgia [21]

Answer:

Step-by-step explanation:

0.2*12=

2 2/5

3 0
3 years ago
Match the verbal expression (term) with its algebraic expression (definition).
UkoKoshka [18]

The matching of definitions and terms are done below.

  1. Some number increased by two ⇒ b + 2
  2. A variable decreased by two ⇒ x – 2
  3. Product of an unknown value and two ⇒ 2z
  4. Quotient of some number and two ⇒ a ÷ 2
  5. An unknown value squared ⇒ y²

<h3>What is Algebra?</h3>

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Match the verbal expression (term) with its algebraic expression (definition).

Some number increased by two ⇒ b + 2

A variable decreased by two ⇒ x – 2

Product of an unknown value and two ⇒ 2z

Quotient of some number and two ⇒ a ÷ 2

An unknown value squared ⇒ y²

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ1

6 0
2 years ago
I have some cheese. I used
hram777 [196]
<h3>Answer:     2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0
3 years ago
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