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3 years ago

12

Remind write the equation of the line y=1/3(x+2). He solved for x and got x=3y-2. which of the following is a equivalent equatio

n for x?

1 answer:

jekas [21]3 years ago

3 0

Answer:

Step-by-step explanation:

multiply 1/3 by x and 3

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Determinar la longitud de la hipotenusa del siguiente triángulo si se conocen las medidas que se indican de los demás triángulos

Zina [86]

it helps a lot in math us it won't let me do it

3 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

4 years ago

What is the Volume of the shape below?

Leona [35]

Answer:

v=720m^3

Step-by-step explanation:

v=lwh

volume=length x width x height

v=15 x 8 x 6

v=720m^3

hope this helps :)

5 0

3 years ago

Read 2 more answers

Please help with at least one question.

Cloud [144]

Okay, first off negative is well negative and since there is no other negatives, -5/7 is least (making it go first). Second, what is smaller 3/5 or 2/9, remember that the bigger the denominator the smaller the piece.

[/] [/] [/] [] [] = 3/5

[/] [/] [] [] [] [] [] [] [] 2/9

At the end it should be -5/7, 2/9 , 3/5. This method can go the same for problems like these...Hope it helps!

7 0

3 years ago

Please someone help please pls

mario62 [17]

Answer:

h= $h= \frac{5R^{3} }{LU}$

Step-by-step explanation:

1.) You must isolate the h from the equation by dividing both sides by L (or multiply by its reciprocal, which in this case, the reciprocal on L is $\frac{1}{L}$ .....So it would look like:

$(\frac{1}{L} )*\frac{5R^{3} }{U} = \frac{L}{h}* (\frac{1}{h} )\\$

2.) Simplify the equation if you need to (in this case, its not needed)

$\frac{5R^3}{LU} =h$

That's your answer :)

3 0

3 years ago