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UkoKoshka [18]
3 years ago
11

Consider points R, S, and T. Point S is in the middle. Point R is below and to the left of point S. Point T is below and to the

right of point S. Which statement is true about the geometric figure that can contain these points? No line can be drawn through any pair of the points. One line can be drawn through all three points. One plane can be drawn so it contains all three points. Two planes can be drawn so that each one contains all three points.
Mathematics
2 answers:
KonstantinChe [14]3 years ago
5 0

Answer:One plane can be drawn so it contains all three points.

Step-by-step explanation:

Points  R,S,T are given .  

If the three  points are co-linear, there are infinitely many planes through the line that contains the three points.

If we  have three distinct points in 3-space then there is a plane that contains these three points.

The third statement holds true for three points R,S and T.

Dovator [93]3 years ago
5 0

Answer:

Answer:One plane can be drawn so it contains all three points.

Step-by-step explanation:

Took the test :P

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9,220,000,000 in scientific notation
Roman55 [17]

Answer:

9.22×10^9

Step-by-step explanation:

The number must be written with

- a number between 1-10

- multiplied by a power of 10

The power of 10 tells you how many times you moved the decimal.

8 0
4 years ago
You deposit $600 in a account earning 5% interest compounded annually. How much will you have in the account in 15 years?
Kisachek [45]

Answer:

$1050 in total including the interest.

Step-by-step explanation:

The answer is 1050 because 5% of 600 is 30 and 30 multiplied by 15 is 450, and 600 plus 450 is 1050

7 0
3 years ago
Find the equation of the perpendicular bisector of a line segment whose end points are (-3,9) and (-1,5)
timofeeve [1]

First find the equation of y.

y=mx+n=\frac{\Delta y}{\Delta x}x+n

Find the slope m.

m=\frac{5-9}{-1-3}=\frac{-4}{-4}=1.

Pick one point, I'll pick (-3, 9). Insert coordinates in equation then compute n.

9=1(-3)+n\implies n=12.

The equation of a line y is:

y=x+12.

The perpendicular line y_{\perp} is same like the normal line except its slope m becomes:

k=-\frac{1}{m}=-1.

The equation of a perpendicular bisector is thus:

y_{\perp}=-x+12.

Hope this helps.

6 0
4 years ago
Read 2 more answers
What is tan 11pie/6?
Luden [163]

Answer:

= - √3/3

Step-by-step explanation:

Tan ( 11π/6)

= Tan ( (12π - 11π)/6)

= Tan ( 2π  - π/6)

using Tan ( A - B) = (Tan A - TanB)/(1 + TanATanB)

A = 2π   B = π/6

= (Tan 2π - Tan π/6)/( 1 + Tan2π * Tan(π/6)

Tan 2π = 0

=> ( 0 - Tan π/6)/(1  + 0)

= - Tan π/6

Tan π/6 = √3/3

= - √3/3

3 0
3 years ago
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Murljashka [212]

Answer:

Sure it gonna be 10.99 units

Step-by-step explanation:

OK so u have to

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So ur radius is de r=7

Then continue and u shld get 10.99......

6 0
3 years ago
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