Question

What is the 37th term of the arithmetic sequence with the first term -39 and the common difference of 8.

Answer 1

Answer:

$a_{37}=249$

Step-by-step explanation:

A sequence that has a common difference is an arithmetic sequence:

$a_n=a_1+(n-1)d$

where aₙ is the nth term, n is the index, and d is the common difference.

In your question:

• n = 37
• a₁ = -39
• d = 8

Plug those into the formula:

$a_{37}=-39+(37-1)8$

Then solve:

$a_{37}=-39+(36)8\\a_{37}=-39+288\\a_{37}=249$