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sattari [20]
2 years ago
10

Draw the image of \triangle ABC△ABCtriangle, A, B, C under a dilation whose center is PPP and scale factor is \dfrac{1}{3} 3 1 ​

start fraction, 1, divided by, 3, end fraction.
Mathematics
1 answer:
zavuch27 [327]2 years ago
8 0

Dilating the triangle ABC would create another triangle whose size is different from the triangle ABC

<h3>How to dilate the triangle?</h3>

From the complete question, we have the following coordinates:

  • Point A = (-4,5)
  • Point B = (7,-7)
  • Point C = (-2,2)
  • Point P = (1,-4)
  • Scale factor, k = 1/3

The dilation rule across the center P is:

(x, y) --> (1/3x – 1, 1/3y + 4)

So, the coordinates of the image of the triangle are:

A' =  (-1/3 * 4 – 1, 1/3 * 5 + 4)

A' =  (-7/3, 17/3)

B' =  (1/3 * 7 – 1, -1/3 * 7 + 4)

B' =  (4/3, 5/3)

C' =  (-1/3 * 2 – 1, 1/3 * 2 + 4)

C' =  (-5/3, 14/3)

From the above computation, the coordinates of the new triangle is:

A' =  (-7/3, 17/3)

B' =  (4/3, 5/3)

C' =  (-5/3, 14/3)

See attachment for the image of triangle ABC

Read more about dilation at:

brainly.com/question/16752437

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9. Miguel measures 5 kg of rice. One kilogram is approximately equal to 2.2 pounds. Which
Nitella [24]

Answer: 11

Step-by-step explanation:

One kilogram is equal to 2.2 pounds so all you would have to do is multiply 2.2 x 5 and you get 11. :)

8 0
4 years ago
2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.
Fudgin [204]

Answer:

\sf t_{20}= 0

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

      \sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }

6th term is 14 ⇒ \sf t_6 = 14

                a + (6 - 1)d = 14

                    a  +  5d = 14  --------------(I)

14th term is 6 ⇒\sf t_{14} = 6

             a + (14-1)d = 6

                  a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

        (I)          a + 5d = 14

        (II)         a + 13d = 6

                    <u>-    -          -</u>

                            -8d = 8

                               d  = 8 ÷(-8)      

                              \sf \boxed{\bf d= (-1)}

Plugin d = -1 in equation (I)

a + 5(-1) = 14

      a -5  = 14

             a = 14 + 5

             \sf \boxed{\bf a = 19}  

20th term:

 \sf t_{20}= 19 + 19*(-1)

       = 19 - 19

   \sf \boxed{\bf t_{20} = 0}

8 0
2 years ago
Read 2 more answers
Please Help!!
GarryVolchara [31]

Answer:

D:) (2,2,) is the Answer

Step-by-step explanation:

Solve the following system:


{X - 2 Y = -2 | (equation 1)


{3 X - 2 Y = 2 | (equation 2)



Swap equation 1 with equation 2:


{3 X - 2 Y = 2 | (equation 1)


{X - 2 Y = -2 | (equation 2)



Subtract 1/3 × (equation 1) from equation 2:


{3 X - 2 Y = 2 | (equation 1)


{0 X - (4 Y)/3 = (-8)/3 | (equation 2)



Multiply equation 2 by -3/4:


{3 X - 2 Y = 2 | (equation 1)


{0 X+Y = 2 | (equation 2)



Add 2 × (equation 2) to equation 1:


{3 X+0 Y = 6 | (equation 1)


{0 X+Y = 2 | (equation 2)



Divide equation 1 by 3:


{X+0 Y = 2 | (equation 1)


{0 X+Y = 2 | (equation 2)



Collect results:


Answer:  {X = 2 , Y = 2

4 0
3 years ago
Read 2 more answers
I need help with is problem.​
ad-work [718]

Step-by-step explanation:

A function f(x) can be scaled by a factor of "a" and translated by (h,k) by the relation:

f(x) -> a f(x-h)+k

substitute f(x) by sqrt(x), then

sqrt(x) -> a*sqrt(x-h) + k

So the given equation is derived from f(x) = sqrt(x), hence a radical function.

8 0
3 years ago
Read 2 more answers
Any one help me with this plsss and ni links plss!!
Bas_tet [7]

Answer:

6. D.

7.  F.

8. A.

9. B.

10. C.

Step-by-step explanation:

6.     9 + (12 - 10)

       12 - 10 = 2

        9 + 2 = 11

7.      (20 - 15) x 2

        20 - 15 = 5

         5 x 2 = 10

8.      10 ÷ 5 + 7

         10 ÷ 5 = 2

          2 + 7 = 9

9.        6 + 2 x 3

           2 x 3 = 6

           6 + 6 = 12

10.        (2 x 4) + 8

             2 x 4 = 8

             8 + 8 = 16

Let me know if this helps!

4 0
3 years ago
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