Answer:
50% of the offspring is expected to be heterozygous for hair length.
Explanation:
50% of the offspring is expected to be heterozygous for hair length.
Heterozygous short hair (Hh)
Long hair cat (hh)
When both of them are crossed they produces offspring with genes:
Hh, Hh, hh, and hh
Hh - Heterozygous short hair
hh- dominant long hair.
So we can infer that 50% of the offspring (2 out of 4) is expected to be heterozygous for hair length, which is heterozygous short hair.
Answer:
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Explanation:
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Answer:
There is no chance that a child of one parent who carries CF gene is born having Cystic Fibrosis if the other parent does not carry the CF gene.
Explanation:
Second child born to Chloe’s mother and stepfather will have Cystic Fibrosis only if they inherit one CF gene from each parent. Since stepfather is not carrier of CF gene, development of the disease at child is not possible.
A person who has inherited one CF gene from his/her parent will be a CF gene carrier, but will never develop Cystic Fibrosis. However as he/she a carrier of the CF gene, they can pass it on to their own child.