Answer:
36
Step-by-step explanation:
Triangle FED and Triangle AEC are similar.
That means, the ratio of corresponding sides are equal. Thus we can say:
![\frac{ED}{DF}=\frac{EC}{CA}](https://tex.z-dn.net/?f=%5Cfrac%7BED%7D%7BDF%7D%3D%5Cfrac%7BEC%7D%7BCA%7D)
Also, since EC is 39 and D is the midpoint, ED and DC are half of that. Hence ED = 39/2 = 19.5
Now we can use the ratio to solve for AC:
![\frac{19.5}{18}=\frac{39}{CA}\\19.5CA=18*39\\19.5CA=702\\CA=\frac{702}{19.5}CA=36](https://tex.z-dn.net/?f=%5Cfrac%7B19.5%7D%7B18%7D%3D%5Cfrac%7B39%7D%7BCA%7D%5C%5C19.5CA%3D18%2A39%5C%5C19.5CA%3D702%5C%5CCA%3D%5Cfrac%7B702%7D%7B19.5%7DCA%3D36)
Hence, AC = 36
Answer:YES
Step-by-step explanation:i have no clue
Answer:
<em>x ≥ 2</em>
Step-by-step explanation:
Distribute 8:
8 (3.5x - 2) ≥ 40
28x - 16 ≥ 40
Add 16:
28x ≥ 40 + 16
28x ≥ 56
Divide by 28:
x ≥ 56 ÷ 28
x ≥ 2
Answer:
0.005 `; 0.00499 ;
No, because np < 10 ;
2000
Step-by-step explanation:
Given that:
Number of samples , n = 100
Proportion, p = x / n
p = 1 / 200
= 0.005
p = μ
Standard deviation of sample proportion :
σp = sqrt((p(1 - p)) / n)
σp = sqrt((0.005(1 - 0.005)) / 200)
σp = sqrt((0.005(0.995)) / 200)
σp = sqrt(0.004975 / 200)
σp = sqrt(0.000024875)
σp = 0.0049874
σp = 0.00499
np = 100 * 0.005 = 0.5
n(1 - p) = 100(1-0.05) = 95
Smallest value of n for which sampling distribution is approximately normal
np ≥ 10
0.005n ≥ 10
To obtain the smallest value of n,
0.005n = 10
n = 10 / 0.005
n = 2000