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cupoosta [38]
3 years ago
11

What is the following product? Assume x>/=0 ^3sqrt(x^2)*^sqrtx^3

Mathematics
1 answer:
RoseWind [281]3 years ago
7 0

Answer:

x(\sqrt[12]{x^5} )

Step-by-step explanation:

We need to remember 2 rules when doing these:

1. \sqrt[n]{x^a} =x^{\frac{a}{n}}

2. x^a*x^b=x^{ab}

Using these 2 rules, we can simplify the product (steps shown below):

\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )

Rearranging, we see that it is the third choice.

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Answer:

123123 3213123 12312 dasdsd aw dasd sda asdasd

Step-by-step explanation:

3 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1
Sphinxa [80]

Answer:

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

Step-by-step explanation:

Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.

a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

8 0
3 years ago
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A donut shop requires customers to spend at least $4 in order to use their debit card to pay for a purchase. Maya wants to buy a
Anuta_ua [19.1K]

Answer:            

x+$1.20 ≥ $4

4 0
2 years ago
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which graph represents the solution set of the system of inequalities? (is my selected answer correct, if not please help!!)
algol [13]

Answer:

the graph on the right-top

Step-by-step explanation:

Transferring an "x" to the right side in x+y\ge-3, we get y\ge -x-3

The system of inequalities is

\left \{ {{y

We have y=2x+2 - ascending function with a=2, b=2

b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.

y=-x-3 - descending function with a=-1, b=-3

y<2x+2 is an area below the ascending function and we see that on the left-

y\ge-x-3 is an area above the descending function

On the left-down we have an area above both functions, so we refuse this picture

Right-top is correct


7 0
3 years ago
What is the m?<br> -8 + 4m = 2
IgorLugansk [536]
Exact Form : 5/2
Decimal Form : 2.5
Mixed number Form : 2 1/2
8 0
3 years ago
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