2) A 0.4 kg ball moves in horizontal circle of radius 3 mat speed of 100m/s. What
1 answer:
9514 1404 393
Answer:
1333.3 N
Step-by-step explanation:
The centripetal acceleration is given by ...
a = v^2/r
a = (100m/s)^2/(3 m) = (10^4)/3 m/s^2
Then the force on the ball is ...
F = Ma = (0.4 kg)(10^4)/3 kg·m/s^2 ≈ 1333.3 N
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Step-by-step explanation:
4 : 3
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I suppose its 7, subtracted
Answer:
AC = 52
Step-by-step explanation:
Add the segment lengths together.
AB + BC = AC
22 + 30 = 52
