Question

2) A 0.4 kg ball moves in horizontal circle of radius 3 mat speed of 100m/s. What

Answer 1

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Answer:

  1333.3 N

Step-by-step explanation:

The centripetal acceleration is given by ...

  a = v^2/r

  a = (100m/s)^2/(3 m) = (10^4)/3 m/s^2

Then the force on the ball is ...

  F = Ma = (0.4 kg)(10^4)/3 kg·m/s^2 ≈ 1333.3 N