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evablogger [386]
3 years ago
11

2) A 0.4 kg ball moves in horizontal circle of radius 3 mat speed of 100m/s. What

Mathematics
1 answer:
ladessa [460]3 years ago
3 0

9514 1404 393

Answer:

  1333.3 N

Step-by-step explanation:

The centripetal acceleration is given by ...

  a = v^2/r

  a = (100m/s)^2/(3 m) = (10^4)/3 m/s^2

Then the force on the ball is ...

  F = Ma = (0.4 kg)(10^4)/3 kg·m/s^2 ≈ 1333.3 N

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You need to buy tissue paper sheets to cushion gifts being placed inside a box. The box is 12 inches wide by 16 inches long. The
Kay [80]

Answer:

Area of tissue paper is 384 square inches.

Step-by-step explanation:

Given:

Length of box = 16 inches.

Width of the box = 12 inches.

We need to find find the area of the tissue paper.

But It is given that the area of the tissue paper sheet is based on twice the length times the width of the box.

Hence Framing in equation form we get;

Area of tissue paper = 2(length\ of \ box \times width \ of \ box)

Hence Substituting the given values we get;

Area of tissue paper = 2(12\times 16) = 2\times 192 = 384 in^2

Hence Area of tissue paper is 384 square inches.

7 0
2 years ago
Find x <br> –3(x – 4) + x = 2x – 12
raketka [301]

Answer:

x=6

Step-by-step explanation:

3 0
2 years ago
How do I find the area of the shaded region? Thanks!!
bazaltina [42]

Answer:

The radius of a circumcircle of an equilateral triangle is equal to (a / √3), where ‘a’ is the length of the side of equilateral triangle.

Circle Radius = 16 / sq root (3)

Circle Radius = 9.237604307

Circle Area = PI * radius ^ 2

Circle Area = PI * 85.3333333333

Circle Area = 268.083

Equilateral Triangle area = side^2 * sq root (3) / 4

Equilateral Triangle area = 16^2 * 0.4330127019

Equilateral Triangle area = 110.85

Shaded region = 268.083 - 110.85

Shaded region = 157.233

Step-by-step explanation:

7 0
3 years ago
3. Find the measure of side DF. See image below.
ad-work [718]

Answer:

d. 5.25

Step-by-step explanation:

make it into two fractions: 6/8 = x/7

solve for x by cross multiplying.

4 0
3 years ago
8x^2+23=823<br><br> whats going to be the answer I got 0 am I right?
Naily [24]
1) No; you are incorrect.  "0" is NOT a solution.

Plug in "0" for "x" ;

8*0² + 23 =? 823? ; 

8*0  + 23 =? 823? ;

  0 + 23 = ? 823 ? ;  No! ;  "0 + 23 = 23 " ; NOT "823" .
_________________________________________________
2)  The answers:  x = 10, -10 ; or, write as:  x = ± 10 .
_________________________________________________

To solve:

GIven:  8x² + 23 = 823 ; 

Subtract "23" from EACH SIDE of the equation:
_____________________________________________
           8x² + 23 - 23 = 823 - 23 ; 
to get:  
           8x²  = 800 ; 

Now, divide EACH SIDE of the equation by "8" ; 

          8x² / 8 = 800 / 8 ;

to get:  x² = 100 ; 

        Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ; 

          √(x²) = √(100) ;

             x  = <span>± 10 .

The answers:  x = 10, -10 ; or, write as:  x = </span><span>± 10 .
_____________________________________________________</span>
5 0
3 years ago
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