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yaroslaw [1]
3 years ago
6

Can you help me on this question -1+3(x+2)=5(1+8x)

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0
The answer is 0 if you just do the problem and solve step by step
skelet666 [1.2K]3 years ago
3 0

Answer:

Its 0.

Step-by-step explanation:

Its just zero.

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Write an equation in slope-intercept form tha is parallel to y=4x-2 and has a y-intercept of -2
alexgriva [62]

Answer:

y = 4x - 2

Step-by-step explanation:

Formula: y = mx + b

Parallel means same slope as original and b is -2.

7 0
3 years ago
I need help on these problems
VikaD [51]
Someone is writing the answer so ill just give you this tip for whenever.
A negitive times a negitive is positive
a negative times a positive is negitive
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8 0
3 years ago
Find the mean of this set of numbers.
mezya [45]
This is how you find the mean of a number:

To find the mean of a number, you need to add up all the numbers listed (so, 5, -11, 7, 12, -1 and 0) and then divide it by the amount of numbers there are listed. 5 + -11 + 7 + 12 + -1 + 0 equals 12, and since there are 6 numbers you then divide 12 by 6. 12 divided 6 is 2. 

So the answer is A. I hope this helped you!
3 0
4 years ago
Read 2 more answers
In the diagram below ab is parallel to cd what is the value of x ?
nydimaria [60]

Answer:

I am pretty sure Its C-120

Step-by-step explanation:

Hope This Helps

3 0
4 years ago
Prove the following limit. lim x → 5 3x − 8 = 7 SOLUTION 1. Preliminary analysis of the problem (guessing a value for δ). Let ε
Temka [501]

\displaystyle\lim_{x\to5}3x-8=7

means to say that for any given \varepsilon>0, we can find \delta such that anytime |x-5| (i.e. the whenever x is "close enough" to 5), we can guarantee that |(3x-8)-7| (i.e. the value of 3x-8 is "close enough" to the limit value).

What we want to end up with is

|(3x-8)-7|=|3x-15|=3|x-5|

Dividing both sides by 3 gives

|x-5|

which suggests \delta=\dfrac\varepsilon3 is a sufficient threshold.

The proof itself is essentially the reverse of this analysis: Let \varepsilon>0 be given. Then if

|x-5|

and so the limit is 7. QED

8 0
3 years ago
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