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2 years ago

9

To cook the meat for the pasta dish takes 2 minutes less than four times the amount of time it takes to boil the noodles. The ti

me to cook the meat is 30 minutes. How long does it take to cook the noodles?

2 answers:

bagirrra123 [75]2 years ago

6 0

10 MIN i think it is :)

velikii [3]2 years ago

4 0

It takes 28 minutes to cook the noodles

7x4=28 +2 =30 but 2 minutes less would be 28,so it takes 28 minutes

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A scuba diver starts at 85 3/4 meters below the surface of the water and descends until he reaches 103 1/5

RSB [31]

Answer:

From his starting point of 85 3/4, he descended 17 9/20 meters

Step-by-step explanation:

We want to know how much farther he went down from his starting point.

103 1/5 - 85 3/4

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tart off by making the denominators of both the numbers the same.

103 1/5 - 85 3/4

103 4/20 - 85 15/20

Make them into improper fractions

2064/20 - 1715/20 = 349/20

Make 349/20 into a mixed fraction

17 9/20

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2 years ago

Question 5: prove that it’s =0

mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that $\cos(\frac{2}{x})$ is a variable number between -1 and 1 (inclusive).

This means that $-1 \le \cos(\frac{2}{x}) \le 1$ .

$x^4 \ge 0$ for all value $x$ . So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

$-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

By squeeze theorem, if $-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

and $\lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L$ , then we can also conclude that $\im_{x \rightarrow} x^4\cos(\frac{2}{x})=L$ .

So we can actually evaluate the "if" limits pretty easily since both are continuous and exist at $x=0$ .

$\lim_{x \rightarrow 0}x^4=0^4=0$

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3 years ago

The area of a trapezoid is 243cm2. The height is 18cm and the length of one of the parallel sides is 10cm. Find the length of th

Irina18 [472]

Answer:

$Side_2 = 17\ cm$

Step-by-step explanation:

Given

Shape: Trapezoid

$Area = 243cm^2$

$Height = 18cm$

$Side_1 = 10cm$

Required

Determine the length of the second parallel side

The area of a trapezoid is:

$Area = \frac{1}{2}(Side_1 + Side_2) * Height$

Substitute values for Area, Height and Side1

$243 = \frac{1}{2}(10 + Side_2) * 18$

Multiply both sides by 2

$2 * 243 = 2 * \frac{1}{2}(10 + Side_2) * 18$

$486 = (10 + Side_2) * 18$

Divide both sides by 18

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Hence;

<em>The length of the second parallel side is 17cm</em>

8 0

3 years ago

Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

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Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

3 years ago

PLEASE HELP LAW OF COSINES

chubhunter [2.5K]

The Law of Cosine states
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so plugging in the numbers gives us

cos $J=(13^2+19^2-11^2)/2(13*19) = 409/494$

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rounding your answer will give you 34°

7 0

2 years ago

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