Answer: The required mean score is 73.93.
Step-by-step explanation: We are given to find the mean score for Mr. Wilson's test scores.
We know that
the mean of a given set of scores is equal to the sum of the scores divided by the number of students who scored the marks.
From the given information, we have
3 students with score 40, 1 student with score 50, 4 students with score 60, 6 students with score 70, 4 students with score 80, 8 students with score 90 and 2 students with score 100.
Therefore, the MEAN score of Mr. Wilson's test scores is given by

Thus, the required mean score is 73.93.