The 57th term of the sequence is 0.
Hope this helps! :)
\(^ ◇^)/
ANSWER TO QUESTION 1
![(1.7\times 10^4)\times(8.5\times 10^{-2})](https://tex.z-dn.net/?f=%281.7%5Ctimes%2010%5E4%29%5Ctimes%288.5%5Ctimes%2010%5E%7B-2%7D%29)
We rewrite to obtain;
![(1.7\times 10^4)\times(8.5\times 10^{-2})=(1.7\times 8.5)\times(10^4\times 10^{-2})](https://tex.z-dn.net/?f=%281.7%5Ctimes%2010%5E4%29%5Ctimes%288.5%5Ctimes%2010%5E%7B-2%7D%29%3D%281.7%5Ctimes%208.5%29%5Ctimes%2810%5E4%5Ctimes%2010%5E%7B-2%7D%29)
Recall this product law of indices
we apply this law to obtain,
![(1.7\times 10^4)\times(8.5\times 10^{-2})=14.45\times10^{4+-2}](https://tex.z-dn.net/?f=%281.7%5Ctimes%2010%5E4%29%5Ctimes%288.5%5Ctimes%2010%5E%7B-2%7D%29%3D14.45%5Ctimes10%5E%7B4%2B-2%7D)
This simplifies to
![(1.7\times 10^4)\times(8.5\times 10^{-2})=14.45\times10^{2}](https://tex.z-dn.net/?f=%281.7%5Ctimes%2010%5E4%29%5Ctimes%288.5%5Ctimes%2010%5E%7B-2%7D%29%3D14.45%5Ctimes10%5E%7B2%7D)
We need to rewrite this in standard form;
![(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^1\times10^{2}](https://tex.z-dn.net/?f=%281.7%5Ctimes%2010%5E4%29%5Ctimes%288.5%5Ctimes%2010%5E%7B-2%7D%29%3D1.445%5Ctimes%2010%5E1%5Ctimes10%5E%7B2%7D)
We apply the product law again to get
![(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^{1+2}](https://tex.z-dn.net/?f=%281.7%5Ctimes%2010%5E4%29%5Ctimes%288.5%5Ctimes%2010%5E%7B-2%7D%29%3D1.445%5Ctimes%2010%5E%7B1%2B2%7D)
This simplifies to
![(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^{3}](https://tex.z-dn.net/?f=%281.7%5Ctimes%2010%5E4%29%5Ctimes%288.5%5Ctimes%2010%5E%7B-2%7D%29%3D1.445%5Ctimes%2010%5E%7B3%7D)
ANSWER TO QUESTION 2
![(6.8\times 10^2)\times(1.3\times 10^{-3})](https://tex.z-dn.net/?f=%286.8%5Ctimes%2010%5E2%29%5Ctimes%281.3%5Ctimes%2010%5E%7B-3%7D%29)
We rewrite to obtain;
![(6.8\times 10^2)\times(1.3\times 10^-3)=(6.8\times 1.3)\times(10^2\times 10^{-3})](https://tex.z-dn.net/?f=%286.8%5Ctimes%2010%5E2%29%5Ctimes%281.3%5Ctimes%2010%5E-3%29%3D%286.8%5Ctimes%201.3%29%5Ctimes%2810%5E2%5Ctimes%2010%5E%7B-3%7D%29)
Recall this product law of indices
we apply this law to obtain,
![(6.8\times 10^2)\times(1.3\times 10^-3)=8.84\times10^{2+-3}](https://tex.z-dn.net/?f=%286.8%5Ctimes%2010%5E2%29%5Ctimes%281.3%5Ctimes%2010%5E-3%29%3D8.84%5Ctimes10%5E%7B2%2B-3%7D)
This simplifies to
![(6.8\times 10^2)\times(1.3\times 10^-3)=8.84\times10^{-1}](https://tex.z-dn.net/?f=%286.8%5Ctimes%2010%5E2%29%5Ctimes%281.3%5Ctimes%2010%5E-3%29%3D8.84%5Ctimes10%5E%7B-1%7D)
This is already in standard form.
Answer:
88.28
Step-by-step explanation:
applying formula of area of triangle, 1/2 X base X height.
given.= base= 16.9 height=10.4
so keeping value in formula.
1/2 X 16.9 X 10.4
on solving it will be 88.28