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3 years ago

I have 2 questions.

Mathematics

2 answers:

frosja888 [35]3 years ago

6 0

I dont know the first answer but the 2nd is dad

LenKa [72]3 years ago

5 0

the change was a positive 3.6 degrees

and second is obviously your dad, and you shouldn't ask us because it is your life but thanks for letting us answer this for you!

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Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

2 years ago

Find what is asked for:

BaLLatris [955]

Ummmmmmmmmm let me think

6 0

3 years ago

I need help on this question

rosijanka [135]

Answer:

11. Volume = 2181.2mm^3

12. Surface Area = 1204.49mm^2

Step-by-step explanation:

We first need to find the hypotenuse side of the triangle using the Pythagorean theorem:

a^2+b^2 = c^2

13.3^2+20.5^2 = c^2

176.89+420.25 = c^2

597.14 = c^2

24.44 = c

Now we can find the volume using the formula:

V = 1/4(16)sqrt-13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2

-20.5^4+2(20.5*24.44)^2-24.44^4

V = 2181.2mm^3

To find the surface area using the surface area formula:

A = (13.3*16)+(20.5*16)+(24.44*16)+1/2sqrt

13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2

-20.5^4+2(20.5*24.44)^2-24.44^4

A = 1204.49mm^2

7 0

3 years ago

The circumference of a globe is 16pi inches. what is the volume of the globe? show your work. use 3.14 for pi

docker41 [41]

Answer:

v=2144.66

Step-by-step explanation:

formula: 4/2 (pi) (r)³

................

3 0

2 years ago

Read 2 more answers

PLEASE HELP FAST NO LINKS!! <br> 3/2 (x-6)= -3

e-lub [12.9K]

Answer:

x= 4

hope this helps!

4 0

3 years ago

Read 2 more answers