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Dovator [93]
3 years ago
14

In parallelogram defg,, DH = x+3 HF= 3y GH=3x-3 and HE =5y + 4

Mathematics
2 answers:
sineoko [7]3 years ago
8 0

Answer:

9 and 4

Step-by-step explanation:

i just took the test

olasank [31]3 years ago
4 0

<u>Answer:</u>

The value of x and y is 9 and 4 units

<u>Solution: </u>

We have,  

DH = x+3; HF= 3y and GH=3x-3; HE =5y + 4

For parallelogram, we know that,

DH=HF

So, (x+3)=3 y\Rightarrow x=(3 y-3)--------- (i)

Again, GH = HE

So, 3x-3 = 5y +4

\Rightarrow3 x=5 y+4+3

x = \frac{(5y+7)}{3} ………. (ii)

Now equating both (i) and (ii) we get,

\Rightarrow3 y-3=\frac{5 y+7}{3}

\Rightarrow3\times(3y-3) = 5y+7

\Rightarrow9y - 9 = 5y +7

\Rightarrow9y-5y=7+9

\Rightarrow4y = 16

\Rightarrow y = 4

So the value of x = 3\times4 -3 = 9

The value of x and y is 9 and 4  units

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