Multiply & Simplify.

A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between the population proportions, ( $p_1-p_2$ ) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

95% confidence interval for ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

4 years ago

Lifetime Fitness charges $90 a month for membership plus $50 per session with a trainer. Which equation can be used to determine

Taya2010 [7]

Answer:

50x / 30/x i think

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the slope of a perpendicular line 2x + y = 6 is answer -2

Firdavs [7]

Answer:

The slope that is perpendicular to the line will be:

$m_2=+\frac{1}{2}$

Step-by-step explanation:

Given the equation

$2x\:+\:y\:=\:6\:$

We know that

$y=mx+b$ is the slope-intercept form of a line where m is the slope and b is the y-intercept.

So, writing the equation in the slope-intercept form

$2x\:+\:y\:=\:6\:$

$\:y=-2x+6$

here

$m=-2$ ∵ $y=mx+b$

As we know that for perpendicular lines, one slope is the negative reciprocal of the other.

Therefore, the slope that is perpendicular to the line will be:

$m_2=+\frac{1}{2}$

3 0

3 years ago

Graphing how can graphing help solve a problem involving ratios

Alexandra [31]

If you have a ratio like 1 yard for 3 feet you can graph that to get a better understanding of size

4 0

4 years ago

Nathan ordered one cheeseburger and one bag of chips for 3.75 jack ordered two cheeseburgers and three bags of chips for 8.25 kn

Elan Coil [88]

Answer:

cheeseburger is $3 and chips is $0.75

Step-by-step explanation:

Let price of cheeseburger be x while price of a bag of chips be y hence for the case of Nathan, we can write the equation as x+y=3.75. Similarly, for Jack, we can write it as 2x+3y=8.25

x+y=3.75 hence x=3.75-y and substituting this into the second equation we have

2x+3y=8.25

2(3.75-y)+3y=8.25

7.5-2y+3y=8.25

y=8.25-7.5=0.75

x=3.75-y=3.75-0.75=3

Therefore, price of cheeseburger is $3 and chips is $0.75

7 0

3 years ago