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pshichka [43]
4 years ago
9

For the following, state the domain, range, and whether the relation is a function.

Mathematics
1 answer:
weeeeeb [17]4 years ago
8 0

Answer:

(a) {(-5, 1), (2, 3), (3, 3), (4, 5)}

DOMAIN:{-5,2,3,4}

RANGE:{1,3,5}

FUNCTION:Yes

(b)DOMAIN:{-2,0,3,4,6}

RANGE:{-3,-2,0,1,2,4}

FUNCTION:No

Step-by-step explanation:

(a) The given relation is {(-5, 1), (2, 3), (3, 3), (4, 5)}

We examine the first coordinates, to see if one of repeats.

Since none of the first coordinates repeated, the relation is a function.

Domain: The refers to the set of all the first coordinates.

Domain:{-5,2,3,4}

The range refers to the set of all the second coordinates.

Range: {1,3,5}

b) The given relation is the mapping diagram. We can see from the diagram that, there is one value in the domain, which is 3, mapping on to two different values in the range. Therefore this relation is not a function.

The domain is {-2,0,3,4,6}

The range is {-3,-2,0,1,2,4}

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Can someone explain
IrinaVladis [17]

Answer:

See below ~

Step-by-step explanation:

Applying the rule (x - 5, y - 3) to the coordinates :

The coordinates are :

  • (2 - 5, -3 - 3) = (-3, -6)
  • (2 - 5, 2 - 3) = (-3, -1)
  • (5 - 5, -3 - 3) = (0, -6)
  • (5 - 5, 2 - 3) = (0, -1)

As evidenced by the rule :

The rectangle is translated <u>5</u> units to the left and <u>3</u> units down.

6 0
2 years ago
Houw would i factor this problem out completely?
kvasek [131]
You can factor out a 3t first, resulting in:
3t(2t^2+3t-5)

Now, let's factor the equation in the middle using the quadratic equation. Plug in the values to the quadratic equation:
\frac{-3\pm \sqrt{3^2-4(2)(-5)}}{2(2)} = -\frac{3\pm \sqrt{49}}{4} = -\frac{3\pm 7}{4}

Simplify, you get your x's:
x = 1, -\frac{5}{2}

To write the equation in simplified form, you just write it this way:
3t(x-1)(2x+5)

That's your answer ^
3 0
3 years ago
Read 2 more answers
Solve for y: 32 5yi = 16x - 40i
Ahat [919]
If you would like to solve 32 + 5yi = 16x - 40i for y, you can do this using the following steps:

<span>32 + 5yi = 16x - 40i
</span>5yi = 16x - 40i - 32      /5
yi = 16x/5 - 8i - 32/5   /i
y = 16x/5i - 8 - 32/5i

The correct result would be <span>y = 16x/5i - 8 - 32/5i.</span>
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3 years ago
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#14 domain and range please help!
s2008m [1.1K]
Domain is the x and the range is the y. so -1,3,1,0 would be the domain and 2,3,5 would be range!
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2 years ago
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