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vredina [299]
3 years ago
12

Find four consecutive even integers with a sum of -52

Mathematics
2 answers:
Komok [63]3 years ago
7 0

Answer:

-16,-14,-12,-10

Step-by-step explanation:

Let the integers be x, x+2,x+4,x+6

ATQ,

x+x+2+x+4+x+6=-52

4x+12=-52

4x=-52-12

x=-64/4

x=-16

Amiraneli [1.4K]3 years ago
3 0

Step-by-step explanation: In this problem we have four consecutive even integers that have a sum of -52. Consecutive even integers can be represented as followed.

<em>X</em>

<em>X + 2</em>

<em>X + 4</em>

<em>X + 6</em>

<em />

Since the sum of these is -52, we can set up an equation to represent this.

X + X + 2 + X + 4 + X + 6 = -52

4x + 12 = -52

4x = -64

X = -16

X + 2 = -14

X + 4 = -12

X + 6 = -10

<em />

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P(B|A) is the probability of event B happening, given that A happened.

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