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vredina [299]
3 years ago
12

Find four consecutive even integers with a sum of -52

Mathematics
2 answers:
Komok [63]3 years ago
7 0

Answer:

-16,-14,-12,-10

Step-by-step explanation:

Let the integers be x, x+2,x+4,x+6

ATQ,

x+x+2+x+4+x+6=-52

4x+12=-52

4x=-52-12

x=-64/4

x=-16

Amiraneli [1.4K]3 years ago
3 0

Step-by-step explanation: In this problem we have four consecutive even integers that have a sum of -52. Consecutive even integers can be represented as followed.

<em>X</em>

<em>X + 2</em>

<em>X + 4</em>

<em>X + 6</em>

<em />

Since the sum of these is -52, we can set up an equation to represent this.

X + X + 2 + X + 4 + X + 6 = -52

4x + 12 = -52

4x = -64

X = -16

X + 2 = -14

X + 4 = -12

X + 6 = -10

<em />

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Answer:

Option b is correct 175

Step-by-step explanation:

n = 7

k = 6

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put k = 6 in above eq. for finding first term

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put k = 7 in above eq. for finding first term

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16, 19 , 22, ...  //Arithmetic series formation

a1 = 16 , a2 = 19

d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms

Using sum forumula for arithmetic series

sum = \frac{n}{2}(2a1 + (n-1)d)

      = \frac{7}{2}(2a1 + (7-1)d)

      = \frac{7}{2}(2(16) + (6)3)

      =  \frac{7}{2}(32 + 18)    

      =  \frac{7}{2}(50)

      = 7 * 25

      = 175




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