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Colt1911 [192]
3 years ago
14

How many solutions does the following system have? 3x+2y=1 -9x-6y=3

Mathematics
2 answers:
Rudik [331]3 years ago
6 0
3x + 2y = 1...multiply by 3
-9x - 6y = 3
--------------
9x + 6y = 3 (result of multiplying by 3)
-9x - 6y = 3
-------------add
0 = 6 (incorrect)

no solution...these r parallel lines that never intersect

guajiro [1.7K]3 years ago
3 0
Divide second equation by -3
3x+2y=1
other equatin is
3x+2y=1
since same equation, they are same line and lines are infinite so infinite solutions is answe
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Jane made a mistake when writing down a mutliplication , and she multiplied by 54 instead of 45. Her answer was 198 more than it
BARSIC [14]

Answer:

22

Step-by-step explanation:

Given that:

Let number multiplied by 54 = x

Let output = y

x * 54 = y + 198

x * 45 = y

54x = y + 198 - - - (1)

45x = y - - - (2)

Put y = 45x in (1)

54x = 45x + 198

54x - 45x = 198

9x = 198

x = 22

Number multiplied by 54 is 22

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3 years ago
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sasho [114]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
1) PART A : determine the domain and range of the function in the graph.
anzhelika [568]
1) Domain: x is greater than -2 and greater than or equal to 5
Range: y is greater than -1 and less than or equal to 3

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6 0
3 years ago
Determine which functions have two real number zeros by calculating the discriminant, b2 – 4ac. Check all that apply. Please ans
timama [110]
<span>The discriminant of a quadratic equation is the b^2-4ac portion that the square root is taken of. If the discriminant is negative, then the function has 2 imaginary roots, if the discriminant is equal to 0, then the function has only 1 real root, and finally, if the discriminant is greater than 0, the function has 2 real roots. So let's look at the equations and see which have a positive discriminant. f(x) = x^2 + 6x + 8 6^2 - 4*1*8 36 - 32 = 4 Positive, so f(x) has 2 real roots. g(x) = x^2 + 4x + 8 4^2 - 4*1*8 16 - 32 = -16 Negative, so g(x) does not have any real roots h(x) = x^2 – 12x + 32 -12^2 - 4*1*32 144 - 128 = 16 Positive, so h(x) has 2 real roots. k(x) = x^2 + 4x – 1 4^2 - 4*1*(-1) 16 - (-4) = 20 Positive, so k(x) has 2 real roots. p(x) = 5x^2 + 5x + 4 5^2 - 4*5*4 25 - 80 = -55 Negative, so p(x) does not have any real roots t(x) = x^2 – 2x – 15 -2^2 - 4*1*(-15) 4 - (-60) = 64 Positive, so t(x) has 2 real roots.</span>
4 0
4 years ago
Read 2 more answers
I’ll give brainliest help
Alika [10]
Answer:
D (QUESTION AT THE BOTTOM)

Explanation:
C decreases on the Y axis by 3
C increases in the X axis by 6

Doing this on every plot line will move the line ABC to line A’B’C.

Remember:
Y = rise
X = run
6 0
3 years ago
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