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TiliK225 [7]
3 years ago
11

What is the circumference of a circle whose radius is 20 feet? Leave answer in terms of π.

Mathematics
2 answers:
lesantik [10]3 years ago
5 0

Answer:

What is the circumference of a circle whose radius is 20 feet? Leave answer in terms of π.  

A)  10π feet  

B)  20π feet  

<u> C)  40π feet  </u>

 D)  100π feet

Step-by-step explanation:

circumference = 2πr

circumference=2×π×20

circumference=40π

lbvjy [14]3 years ago
3 0

[] Answer []

\boxed{40\pi \ Feet}

[] Explanation []

Area = πr^{2}

Pi = 3.14

Radius = 20

Our Equation:

3.14 * 20 * 2

3.14 * 20 = 62.8 * 2 = 125.6

\boxed{[] \ Eclipsed \ []}

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a. \  \dfrac{625 \cdot m}{27 \cdot n^{11}}

b. \  \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}

By expanding the expression, we get;

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\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}

(b) The given expression is presented as follows;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4

Therefore, we get;

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x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

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