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Iteru [2.4K]
3 years ago
7

Are there fewer squares or triangles? pic have 5 squares and 3 triangles

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0
Fewer triangles. There are 5 squares and 3 triangles with 3 being less then 5 there are less triangles.
NARA [144]3 years ago
7 0
3 is less than 5 There for 3 is less so there is less triangles
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What is the solution to this equation?
tresset_1 [31]

Answer:

x = 9

Step-by-step explanation:

First, we want to isolate variable x on the left side of the equation. We can do this by adding 13 to both sides.

x - 13 + 13 = - 4 + 13

x = 9

8 0
3 years ago
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Make up an equation of the form y = kx +b, the graph of which passes through the following points: A (8, –1) and B (–4, 17)
igor_vitrenko [27]

Answer:

One equation would be y= -1.5x +11

Step-by-step explanation:

Here's a table to show the coordinates

x:             y:

8              -1

-------------------

-4             17

the x coor. 8  goes down by 12 to get to the next x coor. -4.

8-12= -4

the y coor. -1 goes up by 18 to get to the next y coor. 17.

-1+18= 17

therefore 18/-12 is -1.5 which can be your k in y=kx+b.

Check your answer.

-1.5*8= -12 but when you add 11, you get the y coor. -1

Do the same with the other x coor.

-4*-1.5= 6 + 11 =17

11 can be your b in the slope-intercept form equation.

One equation may be y = -1.5x +11

4 0
3 years ago
The angles of a quadrilateral are 140, 80, 60, and 80<br> What type of quadrilateral could it be?
My name is Ann [436]
Your answer is a trapezium 
5 0
3 years ago
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$2665 is compounded annually at a rate of 9% for 1 year
MakcuM [25]

Answer:

$2675

Step-by-step explanation:

7 0
3 years ago
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Snezhnost [94]

Answer:

When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).

Thus, the rule is:

P(x, y) → P'(x, -y)

Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

4 0
3 years ago
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