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Nikitich [7]
2 years ago
13

In the statement

Mathematics
1 answer:
Ghella [55]2 years ago
6 0

Answer: True

Step-by-step explanation:

True

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Find the equation of the quadratic function with zeros at -1 and 1 and a vertex a t0,-6
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hello :

the quadratic function is :

<span>  f(x) = a(x-1)(x+1)

but ; f(0) = -6</span>

a(0-1)(0+1) = -6 

-a = -6

a=6


<span>the equation is : 6(x-1)(x+1) = 0</span>
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Find the equation for a parabola with its focus at (0, 3) and a directrix of y = -3.
GrogVix [38]

Answer:

y = (1/12)x^2

Step-by-step explanation:

The vertex of this parabola is halfway between (0, 3) and the directrix, y = -3; that is, it's at (0, 0).

The applicable equation for this vertical parabola is 4py = x^2, where p is the distance between the vertex and the focus.  Here that distance is p = 3.

Thus, 4py = x^2 becomes 4(3)y = x^2, or 12y = x^2, or y = (1/12)x^2.

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3 years ago
290 divided by 70 estimate to
labwork [276]
290 divides by 70 is 4.14285...
Estimated to the ten thousandths: 4.1429
Estimated to the thousandths: 4.143
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steposvetlana [31]

3x + 18 = 147

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I did not get the right answer, please help.​
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