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3 years ago

Can someone help me plz

Mathematics

1 answer:

FrozenT [24]3 years ago

3 0

Answer:

I cant see it?

Step-by-step explanation:

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Rationalize the denominator. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B%5Csqrt%7Bx%2B3%7D%20%7D" id="TexFormula1" title

Jobisdone [24]

The result after rationalizing is $\frac{9\sqrt{x+3} }{x+3}$ .

<h3>What is Rationalization?</h3>

Rationalization can be considered as the process used to eliminate a radical or an imaginary number from the denominator of an algebraic fraction.

Here, given fraction

$\frac{9}{\sqrt{x+3} }$

Multiply and divide by $\sqrt{x+3}$ , we get

$\frac{9}{\sqrt{x+3} } \frac{\sqrt{x+3} }{\sqrt{x+3} }$ = $\frac{9\sqrt{x+3} }{x+3}$

Thus, the result after rationalizing is $\frac{9\sqrt{x+3} }{x+3}$ .

Learn more about Rationalization from:

brainly.com/question/15837135

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6 0

2 years ago

Please... time is almost up somebody?

Leya [2.2K]

5. 80, 16/.2=80
6. 679, 750-70.75
7. 7.82, 10-2.18
8. 36.07, 29.62+1.29+ 1.29+ 1.29+ 1.29+ 1.29

6 0

3 years ago

List the first five multiples of 7?

Maurinko [17]

The first 5 factors of 7 are 7,14,21,28,35

3 0

4 years ago

If the number of equally likely sample outcomes of a single stage of an experiment is 4, what is the total number of elements in

frutty [35]

OC. 64

because it’s 64

6 0

3 years ago

Read 2 more answers

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

4 years ago