Answer:
(multiply both sides by 6)
6×
-10×6=-2h×6
(simplify)
4h+4-60=-12h
4h-56=-12h
(move constant to the right side and variable to the left)
4h+12h=56
16h=56
(divide both sides by 16)
h=7/2
Answer:
5 hours
Step-by-step explanation:
Lillian is deciding between two parking garages.
Let the time required to park be represented by t
A = Amount
From Garage A
A = the amount Garage A would charge if Lillian parks for t hours
B = the amount Garage B would charge if Lillian parks for t hours.
Garage A
Garage A charges an initial fee of $4 to park plus $3 per hour.
A = $4 + $3 × t
A = 4 + 3t
Garage B charges an initial fee of $9 to park plus $2 per hour.
B = $9 + $2 × t
B = 9 + 2t
The hours parked, t, that would make the cost of each garage the same is calculated by equating A to B
A = B
4 + 3t = 9 + 2t
Collect like terms
3t - 2t = 9 - 4
t = 5 hours
Therefore, the hours parked, t, that would make the cost of each garage the same is 5 hours
Answer:
sorry i don't know
Step-by-step explanation:
you did the same thing to me just for points
The easiest way to do it (for me) is to find 1% of the regular price. I think we can round the prices to $70,00 and $40,00 to show nice percentage.
70 / 100 = 0,7
So 1% is 0,7. Now we can divide $40,00 by 0,7 to calculate how many percent it is:
40 / 0,7 = 57 (after rounding it to the nearest whole number)
So the discount was 100 - 57 = 43 percent.
Doublecheck (optional):
70 * 57% =
= 70 * 57/100 =
= 7 * 57/10 =
= 7 * 5 7,10 =
= 7 * 5,7 =
= 39,9 (the price after the discount)
70 * 43% =
= 70 * 43/100 =
= 7 * 43/10 =
= 7 * 4 3/10 =
= 7 * 4,3 =
= 30,1 (the value of the discount)
The difference of 0,1 is because of the rounding, but it's correct.