Answer:
<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>142</u></em><em><u>°</u></em></h2>
Step-by-step explanation:
This is because,
They are <em><u>Vertically</u></em><em><u> </u></em><em><u>Opposite</u></em><em><u> </u></em><em><u>Angles</u></em><em><u>. </u></em>
4 option is incorrect which is EDCFGA
Z + Y = a right angle so need to equal 90 degrees:
Find Z & Y:
2b + 6 + 3b -1 = 90
5b +5 = 90
5b = 85
b = 85/5
b = 17
Z = 2(17) +6 = 34+6 = 40 degrees
Y = 3(17) - 1 = 51 - 1 = 50 degrees
Y & W make a straight line so need to equal 180:
W = 180 - 50 = 130 degrees.
Z & X make a straight line so need to equal 180:
X = 180 - 40 = 140 degree.
Answer:
8,160 lei
Step-by-step explanation:
<u><em>The question in English is</em></u>
136 children came to the ice rink in the morning, and three times in the afternoon. How much money was collected on the tickets sold, if an entrance ticket costs 15 lei?
step 1
Find the total number of children that came to the ice rink
we know that
The number of children that came to the ice rink in the morning was 136
The number of children that came to the ice rink in the afternoon was (136*3)=408
To find out the total number of children that came to the ice rink , adds the number of children that came in the morning plus the number of children that came in the afternoon
so
step 2
To find out the total money collected, multiply the total number of children by the cost of one ticket entrance
so
Answer: 27! - [22! * 6!]
Step-by-step explanation:
Decorations available = 12 blue ballons, 9 Green Lanterns and 6 red ribbons
To determine the number if ways of arrangement for if the ribbons must not be together, we must first determine the number of possible ways to arrange these decorations items if there are no restrictions.
Total number of ways to arrange them = [12+9+6]! = 27! = 1.089 * 10^28
If this ribbons are to be arranged distinctively by making sure all six of them are together, then we arrange the 6 of them in different ways and consider the 6ribbons as one entity.
Number of ways to arrange 6 ribbons = 6!.
To arrange the total number of entity now that we have arranged this 6ribbons together and taking them as one entity become: = (12 + 9 + 1)!. = 22!
Number of ways to arrange if all of the ribbons are taken as 1 and we have 22 entities in total becomes: 22! * 6!.
Hence, to arrange these decoration items making sure no two ribbons are together becomes:
= 27! - (22! * 6!)
= 1.08880602 * 10^28