1000 ways
First digit of codes: 10 choices (0-9)
Second digit of codes: 10 choices (0-9)
Third digit of codes: 10 choices (0-9)
10*10*10 = 1000
Answer:
Step-by-step explanation:
8y+14=3y+49
-3y . -3y
5y+14=49
-14 -14
5y=35 divide both sides by 5
y=7
Post the problem directly in the question, thanks
If the sum of two consecutive even integers is 234, the larger integer would be 118, and the smaller integer would be 116. This is because you take 234 and divide by 2. Take those numbers and add one to one side, and take away one number on the other side.
If you divide 270 / 1.35 you get 200 so 1.35 times 200 = 270