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pentagon [3]
3 years ago
10

There is a claim from the 1960s that 35% of women had college educations in the 60s. To prove it had increased in the 70s, we ra

ndomly pulled education records of 395 women and found that 161 had college educations. Running a hypothesis test, we found a p-value of 0.0088. The interpretation of the p-value is___.
Mathematics
1 answer:
kipiarov [429]3 years ago
7 0

Answer: The National Center for Education Statistics (NCES) collects, analyzes and makes available data related to education in the U.S. and other nations. Hope this helped

Step-by-step explanation: how are you?

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There are 12 boys and 16 girls in Marco's class (including Marco).What is the probability that a student chosen at random from M
Len [333]

Answer: 3:4 ratio or 3/4

Step-by-step explanation:

5 0
2 years ago
PLEASE HELP ILL MARK BRAINLIEST !!!
Alexus [3.1K]

Answer:

a) the common difference is 20

b) x_8=115 , x_{12}=195

c) the common difference is -13

d) a_{12}=52, a_{15}=13

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: x_n=x_1+(n-1)d

We know common difference d= 20, we need to find x_1

Using x_3=16 we can find x_1

x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25

So, We have x_1 = -25

Now finding x_8

x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115

So, \mathbf{x_8=115}

Now finding x_{12}

x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195

So, \mathbf{x_{12}=195}

c) what is the common difference of the sequence a_m

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: a_n=a_1+(n-1)d

We know common difference d= -13, we need to find a_1

Using a_7=104 we can find x_1

a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195

So, We have a_1 = 195

Now finding a_{12} , put n=12

a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52

So, \mathbf{a_{12}=52}

Now finding a_{15} , put n=15

a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13

So, \mathbf{a_{15}=13}

5 0
3 years ago
Which Expression is equivalent to 48z +42q<br><br> A) 6(8z+7q)<br><br> B) 6*8z+7q<br><br> C) 8z+7q
Butoxors [25]

Answer:

6(8z+7q)

Step-by-step explanation:

48z+42q

Factor out 6.

6(8z+7q)

5 0
3 years ago
A class of 24 students went on a picnic. They had a choice between having a turkey sandwich or a vegetarian sandwich. Eighteen s
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I believe it is the ratio 3 : 1.

<u>18 students chose the turkey sandwich</u>.

Since the class has a total of 24 students, we can deduce that <u>6 students chose the vegetarian sandwich</u>.

This gives us a ratio of 18 : 6.

When simplified, we get a ratio of 3 : 1.

5 0
3 years ago
2a + 4b + c =5 <br> x =-2 <br><br> a - 4b = -6<br> y=1
cricket20 [7]
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10 [2] b-c=15 [3] a-2b+c=-5 Equations Simplified or Rearranged :<span><span>  [1] 2a + c = -10 </span><span>  [2] - c + b = 15 </span><span>  [3] a + c - 2b = -5 </span></span>Solve by Substitution :

// Solve equation [3] for the variable  c  
 

<span> [3] c = -a + 2b - 5 </span>

// Plug this in for variable  c  in equation [1]

<span><span>  [1] 2a + (-a +2?-5) = -10 </span><span>  [1] a = -5 </span></span>

// Plug this in for variable  c  in equation [2]

<span><span>  [2] - (-? +2b-5) + b = 15 </span><span>  [2] - b = 10 </span></span>

// Solve equation [2] for the variable  ?  
 

<span> [2] ? = b + 10 </span>

// Plug this in for variable  ?  in equation [1]

<span><span>  [1] (? +10) = -5 </span><span>  [1] 0 = -15 => NO solution </span></span><span>No solution</span>
3 0
3 years ago
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