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liraira [26]
2 years ago
6

4y+8-2y if y=3 what is the answer

Mathematics
1 answer:
exis [7]2 years ago
6 0

Answer:

14.

Step-by-step explanation:

Plug 3 in for y:

= 4(3) + 8 - 2(3)

= 12 + 8 - 6

= 14.

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The wheels on Karen’s rollerblades each have a diameter of 5 cm. How far will the rollerblade travel in one turn of the wheel? U
Ierofanga [76]
To find the distance in one turn of the wheel you have to find the circumference of the wheel.

Circumference = pi x d
= 3.14 x 5
= 15.7 cm

therefore the rollerblade wheel will travel 15.7 cm per rotation

hope this helps! if you did not understand a step or concept please let me know!
8 0
3 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
Help asaaaaap please
katovenus [111]

Answer:

A. 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-5x - 1 ≤ -9

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 1 to both sides:                    -5x ≤ -8
  2. Divide -5 on both sides:             x ≥ 8/5

Here we see that any value <em>x</em> greater than or equal to 1.6 would work as a solution.

Therefore, our answer is A. 1, as it doesn't work as a solution.

3 0
3 years ago
Read 2 more answers
How many thirtieths in 400 sq ft
ozzi
Thirties in 400
ok well we could find out by dividing 400 by 30.
400 / 30 = 13.333333
We Can Round That To 13
Theres Your Answer (13)
7 0
4 years ago
Read 2 more answers
The area of a rectangle is 70 m², and the length of the rectangle is 11 m less than three times the width. Find the dimensions o
11111nata11111 [884]

Step-by-step explanation:

the area of a rectangle is

length × width

in our case

length × width = 70 m²

length = 3×width - 11

we can use this second equation in the first and get

(3×width - 11) × width = 70

3×width² - 11×width - 70 = 0

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 3

b = -11

c = -70

x = (11 ± sqrt((-11)² - 4×3×-70))/(2×3) =

= (11 ± sqrt(121 + 840))/6 =

= (11 ± sqrt(961))/6

x1 = (11 + 31)/6 = 42/6 = 7

x2 = (11 - 31)/6 = -20/6 = -10/3

the negative solution is not applicable for a length in an object.

so, only x1 = 7 m is our solution.

the width of the rectangle is 7 m.

the length = 3×width - 11 = 3×7 - 11 = 21-11 = 10 m

7 0
2 years ago
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