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damaskus [11]
3 years ago
7

If sin 0=1 over square root of 2 find the value of 0

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0
Here is your answer zero will always equal zero.
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The fish population of a lake is decreasing each year. A study is conducted. But, unfortunately some data was lost. The research
Solnce55 [7]

Answer:

F(t) = 18000(0.6666)^{t}

Step-by-step explanation:

The fish population after t years can be modeled by the following equation:

F(t) = F(0)(1-r)^{t}

In which F(0) is the initial population and r is the constant rate of decay.

Year one the fish population was 18000

This means that F(0) = 18000

In year three the fish population was 8000 fish.

Two years later, so F(2) = 8000

F(t) = F(0)(1-r)^{t}

8000 = 18000(1-r)^{2}

(1-r)^{2} = 0.4444

\sqrt{(1-r)^{2}} = \sqrt{0.4444}

1 - r = 0.6666

r = 0.3334

So

F(t) = 18000(0.6666)^{t}

4 0
3 years ago
Danielle invests $2,007 in a retirement
ivanzaharov [21]
Formula For finding Simple interest= Profit x rate x time/ 100

Profit = $2,007 x Rate= 7% x Time = 16 years


2,007 x 7 x 16
__________ = 224,784 ÷100 = 2,247.84
100


Answer :- 2247.84
5 0
3 years ago
Read 2 more answers
You have a truck with two gas tanks. The volume of the larger tank is "8x2 + 2x − 1" in3 and the volume of the smaller tank is "
DaniilM [7]
Tank1+tank2=8x^2+2x-1+7x^2-2x+1

Total=15x^2
7 0
3 years ago
Stan worked 4 years less than Marco.This year Stan has worked 29 years.If b is how long Marco worked, the equation b - 4 = 29 re
MA_775_DIABLO [31]

Answer:

Add 4 on both sides.

In the equation there is a -4.

If -4+4=0, that is how you would get rid of the -4.

But, you need to add 4 to 29 to really get rid of the -4.

So, 29+4 is 33.

b=33

6 0
3 years ago
The 12th term of the arithmetic sequence is 10.5. The 18th term of this sequence is 13.5. Find the common difference and the fir
xxMikexx [17]

Answer:

common difference is 0.5

first term is 5

Step-by-step explanation:

<em>use </em><em>the </em><em>formula</em><em> for</em><em> </em><em>the</em><em> </em><em>nth </em><em>term </em><em>of </em><em>an </em><em>ap </em><em>Tn=</em><em>a+</em><em>(</em><em>n-1)</em><em>d</em>

<em>T12=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>T18=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em>therefore</em><em> </em><em>come </em><em>up </em><em>with </em><em>two </em><em>equations</em>

<em>T12=</em><em>a+</em><em>(</em><em>1</em><em>2</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>0</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>1</em><em>d</em><em>(</em><em>1</em><em>s</em><em>t</em><em> </em><em>equation</em><em>)</em>

<em>T18</em><em>=</em><em>a+</em><em>(</em><em>1</em><em>8</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>3</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>7</em><em>d</em><em>(</em><em>2</em><em>n</em><em>d</em><em> </em><em>equation</em><em>)</em>

<em>then </em><em>solve </em><em>both </em><em>as </em><em>a </em><em>simultaneous</em><em> </em><em>equation</em>

<em>a+</em><em>1</em><em>1</em><em>d</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>1</em><em>7</em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>-6d/</em><em>-</em><em>6</em><em>=</em><em>-</em><em>3</em><em>/</em><em>-</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d=</em><em>0</em><em>.</em><em>5</em>

<em>use </em><em>one </em><em>of</em><em> the</em><em> </em><em>equations</em><em> </em><em>to </em><em>find </em><em>the </em><em>first</em><em> </em><em>term</em>

<em>a+</em><em>1</em><em>1</em><em>(</em><em>0</em><em>.</em><em>5</em><em>)</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>5</em><em>.</em><em>5</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>-</em><em>5</em><em>.</em><em>5</em>

<em>a=</em><em>5</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

<em>please </em><em>mark</em><em> </em><em>as </em><em>brainliest</em>

7 0
3 years ago
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