Answer:
WW WI WB WR IW II IB IR BW BI BB BR RW RI RB RR
Step-by-step explanation:
Answer:
7 + 6
5 + 11
Step-by-step explanation:
the lengths of the two shorter sides of a triangle must add up to more than the length of the third side.
3 + 4 = 7 ≤ 8 no
7 + 6 = 13 > 12 yes
5 + 11 = 16 > 13 yes
4 + 6 = 10 ≤ 12 no
4 + 6 = 10 ≤ 10 no
Answer:

Step-by-step explanation:

Answer:
81/10
Step-by-step explanation:
i just figured it out i really don't have one but i hope it helps
Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.
Substitute the known values into the formula:
x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}
Simplify:
<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>
<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>
<span>x√10=√[2x(x)(x-1)(1)]</span>
<span>x√10=√[2x²(x-1)]</span>
<span>x√10=√(2x³-2x²)</span>
<span>10x²=2x³-2x²</span>
<span>2x³-12x²=0</span>
<span>2x²(x-6)=0</span>
<span>2x²=0 or x-6=0</span>
<span>x=0 or x=6</span>
<span>Therefore, x=6 (you can't have a length of 0).</span>