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marshall27 [118]
3 years ago
6

What is the value of x?

Mathematics
2 answers:
Dovator [93]3 years ago
6 0
R = red one.

g = green one.

b = blue one.

\bf \begin{cases}
r+g=24\\
r+b=10\\
b+g=20
\end{cases}\\\\
-------------------------------\\\\
r+g=24\implies \boxed{r}=24-g
\\\\\\
r+b=10\implies \boxed{24-g}+b=10\implies b=10-24+g
\\\\\\
\underline{b}=-14+g\\\\
-------------------------------

\bf therefore\qquad b+g=20\implies \underline{-14+g}+g=20
\\\\\\-14+2g=20
\\\\\\
2g=34\implies g=\cfrac{34}{2}\implies g=17\qquad 
\begin{cases}
b+g=20\\
b=20-g\\
b=20-17\\
b=3\\
------\\
r+b=10\\
r+3=10\\
r=10-3\\
r=7
\end{cases}
\\\\\\
\stackrel{7}{r}+\stackrel{b}{3}+\stackrel{17}{g}=27
True [87]3 years ago
5 0
Red + green = 24; (1)
red + blue  = 10; (2)
blue + green = 20; (3) 

(1) - (2):
green - blue = 14;  (4)

(3) + (4):
2 * green = 34;
green = 17;

Simple substitution gives:
blue = 3;
red = 7;
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Adult tickets to a play cost $24. Tickets for children cost $18. Tickets for a group of 13 people cost $282. Write and solve a s
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4 0
3 years ago
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A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
ABCD is a parallelogram. Segment AC = 4x + 10. Find the value of x and y.
valkas [14]

Answer:

The values of x and y in the diagonals of the parallelogram are x=0 and y=5

Step-by-step explanation:

Given that ABCD is a parallelogram

And segment AC=4x+10

From the figure we have the diagonals AC=3x+y and BD=2x+y

By the property of parallelogram the diagonals are congruent

∴ we can equate the diagonals AC=BD

That is 3x+y=2x+y

3x+y-(2x+y)=2x+y-(2x+y)

3x+y-2x-y=2x+y-2x-y

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∴ x=0

Given that segment AC=4x+10

Substitute x=0  we have AC=4(0)+10

=0+10

=10

∴ AC=10

Now (3x+y)+(2x+y)=10

5x+2y=10

Substitute x=0, 5(0)+2y=10

2y=10

y=\frac{10}{2}

∴ y=5

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5 0
3 years ago
Please help and add steps!!
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Answer:

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Step-by-step explanation:

7 0
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