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Dominik [7]
3 years ago
8

What is the distance between (1,-5) and (-3,6)​

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

\large\boxed{\sqrt{137}\approx11.7}

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have two points (1, -5) and (-3, 6). substitute:

d=\sqrt{(-3-1)^2+(6-(-5))^2}=\sqrt{(-4)^2+11^2}=\sqrt{16+121}=\sqrt{137}

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If f(x)=5x+1 and g(x)=2f(x)+5 then g(-1)=
ollegr [7]
We know f(x)=5x+1. Plug in f(x) in the g(x) function.
We get g(x)=2(5x+1)+5 Distribute the 2 to 5x and 1.
g(x)=10x+2+5
Simplify to get g(x)=10x+7
Now, we plug in -1 for x.
g(-1)=10(-1)+7
g(-1)=-10+7
g(-1)=-3 
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The triangle on the grid will be translated two units left. which shows the triangle translated 2 units left
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Answer:

Take the coordinates of each vertex (corner point) and subtract 2 from the x-coordinate; leave the y-coordinate alone.

Step-by-step explanation:

Example: If one vertex is the point (5, 3), then it moves left 2 units to (3, 3).

If a vertex is at (-3, 1), then it moves 2 units left to (-5, 1).

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Find sin x/2, cos x/2, and tan x/2 from the given information.. cos x = −15/17, 180° < x < 270°. . sin x/2=. . cos x/2=. .
sukhopar [10]
So base on your question the possible answer to that kind of question and the solution are the following and i hope you will understand the formula and free to ask some questions if needed.

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6 0
3 years ago
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Externally applied mechanical forces acting on a body, such as normal and shear forces, will cause deformation dependent on the
natima [27]

Find the answer in the attachment

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3 years ago
HELP ASAP
Naily [24]

Answer:

y+4 = -\frac{1}{3} (x-1)

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula m = \frac{y_2-y_1}{x_2-x_1} to find the slope. Substitute the x and y values of the given points into the formula and solve:

m = \frac{(-5)-(-4)}{(4)-(1)} \\m = \frac{-5+4}{4-1} \\m = \frac{-1}{3}

So, the slope is -\frac{1}{3}.

2) Use the point-slope formula y-y_1  = m (x-x_1) to write the equation of the line in point-slope form. Substitute values for m, x_1, and y_1 into the formula.

Since m represents the slope, substitute -\frac{1}{3}  in its place. Since x_1 and y_1 represent the x and y values of one point on the line, choose any one of the given points (it doesn't matter which one) and substitute the x and y values of it into the formula. (I chose (1,-4), as seen below). This gives the equation of the line in point-slope form.    

y-(-4) = -\frac{1}{3} (x-(1))\\y+4 = -\frac{1}{3} (x-1)

5 0
2 years ago
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