We have been given a graph that involves Real axis and Imaginary axis.
From that graph we have to choose correct line segment which joins complex numbers 2+2i and -1+3i.
We know that if complex number is (a+bi) then real part "a" is always plotted along x-axis and the imaginary part "b" is always plotted along y-axis just like point (a,b) on x-y graph.
So 2+2i means point (2,2) on x-y graph which is at point B.
similarly -1+3i means point (-1,3) which will be at point A.
So the line segment joining them will be AB
Hence final answer is the line segment AB.
Answer:
x = -1 and y = 18
Step-by-step explanation:
Given the system of equations
y + 8x = 10... 1
2y - 4x = 40 ... 2
From 1; y = 10-8x
Substitute into 2;
2(10-8x) - 4x = 40
20 - 16x - 4x = 40
20 - 20x = 40
-20x = 40 - 20
-20x = 20
x = -1
Recall that y = 10-8x
y = 10 - 8(-1)
y = 10 + 8
y = 18
therefore your answer is x = -1 and y = 18
Answer:
The correct answer is B. ![\sqrt[9]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B9%5D%7B3%7D)
Step-by-step explanation:
The root of a number can be expressed as the number raised to the power whose exponent is a fractional number. The exponent number will be the inverse of the root index.
In this case, three to the two thirds power all raised to the one sixth power is expressed as:

Power of a Power Property: This property states that the power of a power can be found by multiplying the exponents.
So, we multiply the exponents:

The expression would be:

which as a radical expression is:
![\sqrt[9]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B9%5D%7B3%7D)
The four options are expressed as:
a) ![\sqrt[6]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B3%7D)
b) ![\sqrt[9]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B9%5D%7B3%7D)
c) ![\sqrt[18]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B18%5D%7B3%7D)
d) ![\sqrt[6]{3^3}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B3%5E3%7D)
The correct answer is B.
Answer:
To solve for x in equation
we should use Division property of equality.
Step-by-step explanation:
Consider the given equation 
Division property of equality states when we divide both sides of an equation by same non zero number , then also both sides remain equal
Applying Division property of equality to the given equation

Divide both sides by 2.5

We get,

Thus, to solve for x in equation
we should use Division property of equality.

According to this <em>trigonometric function</em>, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{π}{6}}{1} = -\frac{π}{6} \\ Period → \frac{π}{1} = π](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B-%5Cfrac%7B%CF%80%7D%7B6%7D%7D%7B1%7D%20%3D%20-%5Cfrac%7B%CF%80%7D%7B6%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B%CF%80%7D%7B1%7D%20%3D%20%CF%80)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{π}{B} \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B%CF%80%7D%7BB%7D%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to extend the troughs on each end of your graphs, beyond the <em>midline</em>.
* All tangent functions have NO AMPLITUDE.
I am joyous to assist you anytime.