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anyanavicka [17]
3 years ago
7

Hey need help with the 1st 4 multiple choice questions

Advanced Placement (AP)
2 answers:
saul85 [17]3 years ago
6 0
Use the answers above.
Firlakuza [10]3 years ago
3 0
18.D
19.A
20.C
21.B
theses are going to be your answers 
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Which of the following statements is true about immigration to the United States during the last two decades of the nineteenth c
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The correct answer for the question that is being presented above is this one: "(D) The United States government entered into a "gentleman's agreement" to ban immigration from certain countries." The statement that is true about immigration to the United States during the last two decades of the nineteenth century is that <span>The United States government entered into a "gentleman's agreement" to ban immigration from certain countries.</span>
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A boss gives her employee a list of seven tasks to complete within the week. The employee makes a list of the most important tas
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Which excerpt from Tinker v. Des Moines shows how precedent helps
stich3 [128]

Answer:

"Other cases cited by the Court do not, as implied, follow the

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3 years ago
Analyze the key characteristics of the following quadratic function. f(x)=x2‒9 Based on the graph, which statement is not true?
kirza4 [7]

Answer:

C. The graph is always positive.

Explanation:

To solve this, it is basically a process of elimination. A is true since the -9 indicates the function was translated down 9 units, making the vertex lie on the y-axis. B is also true because if you look at the equation from 0 to infinity, the y-values increase. D is also correct because when you solve for the zeros, they do end up being 3 and -3, making the only claim that is not true C, the graph is always positive.

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3 years ago
Limit as x approaches 0 of (2e^x-2)/x
Snowcat [4.5K]

Answer:

Explanation:

\lim_{x \to \ 0} \frac{2e^x-2}{x}

So first, we have to plug in zero and see if we can evaluate this limit simply from that.

When we plug in zero we get: (2e^0-2)/0

e^0 is 1 so we have 2-2/0 or 0/0. So we have an indeterminate form type 0/0.

This means we have to apply L'Hospital's Rule.

As a reminder L'Hospitals Rule is \lim_{x\to \ c} \frac{f'(x)}{g'(x)}

Meaning that we take the derivative of the top and bottom function as the approach some value "c". We can do this with a 0/0 indeterminate form.

So:

The derivative of 2e^x - 2 is just 2e^x

and the derivative of x is 1

So we are left with \lim_{x \to \ 0} 2e^x

Plugging in zero we see this gives us 2 as 2(e^0) = 2(1) = 2.

Hence, \lim_{x \to \ 0} \frac{2e^x-2}{x} = 2

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3 years ago
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