All categories

3 years ago

Hey need help with the 1st 4 multiple choice questions

Advanced Placement (AP)

2 answers:

saul85 [17]3 years ago

6 0

Use the answers above.

Firlakuza [10]3 years ago

3 0

18.D
19.A
20.C
21.B
theses are going to be your answers

You might be interested in

A semiarid climate is BEST suited for what type of agriculture?

dalvyx [7]

<span>C) Herding animals
The asals are ideal for pastoralist activities. The rotational nature that semi arid areas demand is only ideal with herding activities. In as much as the ecosystem is balanced, the areas are viable options for herdsmen.
</span>

6 0

3 years ago

Refer to the passage.

astraxan [27]

Answer:

Farmers growing high-yield crops are more likely to be self-sufficient and thus require less support from the rest of society.

Explanation:

4 0

3 years ago

Read 2 more answers

Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th

lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

$C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2$

Finding the boundaries of the function gives;

$0\times e^{4-0^2} = 0$ and $2\times e^{4-2^2} = 2$

At t = 1, we have $1\times e^{4-1^2} = e^{3} = 20.086$

We find the maximum point as follows;

$\frac{\mathrm{d} \left (t\times e^{4-t^2} \right )}{\mathrm{d} x}=0$

From which we have;

$\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0$

$e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0$

$e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\$

$e^{4-t^2}=0$ or $(1 - 2\times t^2 })=0$

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for 0 ≤ t ≤ 0 1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0

3 years ago

Someone help me on my questions please. :(

kompoz [17]

Sure what’s the question

3 0

2 years ago

Which of the following is not one of the tool of montary policy

Akimi4 [234]

Answer: not sure but I believe its e

Explanation:

The tools of monetary policy work together to keep a healthy economic growth.

* reserve requirements

* open market operations

* discount rate

* government spending

^ I believe that all of these could keep the economy healthy is some sort of way.

8 0

2 years ago