Answer:
Remember that a perfect square trinomial can be factored into the form (a+b)^2
or (a-b)^2
Examples:
(x+2)(x+2) is a perfect sq trinomial --> x^2+4x+4
(x-3)(x-3) is a perfect sq trinomial --> x^2-6x+9
(x+2)(x-3) is not a perfect square trinomial because its not in the form (a+b)^2 or (a-b)^2
Now to answer your question,
for the first one, x^2-16x-64, you cannot factor it so it is not a perfect square trinomial
for the second one, 4x^2 + 12x + 9, you can factor that into (2x+3)(2x+3) = (2x+3)^2 so this is a perfect square trinomial
for the third one, x^2+20x+100 can be factored into (x+10)(x+10) so this is also a perfect square trinomial
for the fourth one, x^2+4x+16 cannot be factored so this is not a perfect square trinomial
Therefore, your answer is choices 2 and 3
Read more on Brainly.com - brainly.com/question/10522355#readmore
Step-by-step explanation:
Answer:
k
Step-by-step explanation:
k=k
Answer:
Sorry I need point's... :(
Step-by-step explanation:
Answer:
i cant view it
Step-by-step explanation:
Answer:
The unlimited-ride passes sold are equal to 168
Step-by-step explanation:
According to given scenario:
x = unlimited-ride passes
y = entrance-only pass
Given that:
50x + 20y = 10,680 -------- eq1
x + y = 282 ------------ eq2
From eq2:
x = 282 - y
Putting value of x in eq1:
50(282 - y) + 20y = 10,680
By simplifying:
14,100 - 50y + 20y = 10,680
14,100 - 30y = 10,680
30y = 14,100 - 10680
30y = 3,480
Dividing both sides by 30
y = 114
Now put value of y in eq2:
x + 114 = 282
x = 282 - 144
x = 168
So, the unlimited-ride passes sold are equal to 168
i hope it will help you!
