2 years ago

Find

Mathematics

2 answers:

soldi70 [24.7K]2 years ago

6 0

Answer:

3x-4 = 0

Step-by-step explanation:

shtirl [24]2 years ago

3 0

A.Domain
Brainliest please

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Chris got 28 out of 35 correct in his test.<br> What fraction of the marks did he get correct?

beks73 [17]

Answer:

4/5

Step-by-step explanation:

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2 years ago

Read 2 more answers

Identify the center and the radius of each.<br><br> x^+y^+26x-22y+281=0

inessss [21]

Answer:

Center (-13,11) , radius 3

Step-by-step explanation:

The given circle has equation

$x^2+y^2+26x-22y+281=0$

We compare this to the general equation.

$x^2+y^2+2ax+2by+c=0$

where (-a,-b) is the center.

This implies that;

2a=26

$\Rightarrow a=13$

2b=-22

b=-11

The center is therefore (-13,11)

The radius is given by

$r=\sqrt{a^2+b^2-c}$

$r=\sqrt{13^2+(-11)^2-281}$

$r=\sqrt{9}$

The radius is 3

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3 years ago

I need help with this question plz

pashok25 [27]

First you need to distribute the exponent into the terms for the first parenthesis.

(-3x²y³)³ = (-3)³ * (x²)³ * (y³)³

= -27 *x⁶ *y⁹

= -27x⁶y⁹

Then you multiply -27x⁶y⁹ by x²y.

You just need to add the exponents of x and y:

-27x⁶⁺²y⁹⁺¹

= -27x⁸y¹⁰

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2 years ago

Simplify -9+5(y+3)-2y

JulijaS [17]

3y+6 is the answer

-9+5(y+3)-2y
-9+5y+15-2y
-9+3y+15
=3y+6

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3 years ago

Please simplify this problem:

joja [24]

Answer:

-52/75

Step-by-step explanation:

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2 years ago