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timurjin [86]
3 years ago
5

Simplify 4x^2+36/4x×1/5x

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0

The simplified version of the expression is this: 5(x² + 9) ÷ x.

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Type SSS, SAS, ASA, SAA, or HL to
Tems11 [23]

9514 1404 393

Answer:

  ASA

Step-by-step explanation:

The shared angle, the marked angle, and the marked sides between those angles are congruent. That is, you have congruent Angle, Side, Angle, so the ASA postulate applies.

6 0
3 years ago
Rectangle with area of 12 square units is dilated by a scale factor of 3. What is the area?
Olegator [25]

Answer:

36 units²

Step-by-step explanation:

rectangle with area of 12 square units is dilated by a scale factor of 3. What is the area?

Scale factor = Dimension of the new shape ÷ Dimension of the original shape.

we use the inverse formula

12 * 3 =<em> </em>

<em>36 units²</em>

<em>-----------------------</em>

check

36 : 12 = 3

the answer is good

7 0
1 year ago
Use an algebraic equation to find the measures of the two angles described below. begin by letting x represent the degree measur
Lina20 [59]
Two angles are said to be supplement when their measure add up to 180 degrees.

Assume that the angle we are looking for is a and its supplement is s (I used s instead of x).

a + s = 180
a = 180 - s ......> equation I

We know that <span>the measure of the angle is eight times greater than its supplement.
This means that:
a = 8s ......> equation II

Substitute by equation II in equation I to get s as follows:
180 - s = 8s
180 = 9s
s = 20 degrees

Substitute in equation I to get the measure of the angle as follows:
a = 180 - s = 180 - 20 = 160 degrees

Based on these calculations:
The measure of the angle is 160 degrees
The measure of its supplement is 20 degrees</span>
4 0
3 years ago
Using distributive property, factor out the GCF and rewrite 54 + 90​
Burka [1]

Answer:

144

Step-by-step explanation:

54+90=144

144-90=54

90+54=144

144-54=90

8 0
3 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
3 years ago
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