Question

The base of a regular pyramid is a hexagon.

Answer 1

ANSWER

$96 \sqrt{3} {cm}^{2}$

EXPLANATION

The area of a regular polygon is

$Area= \frac{1}{2} ap$

where 'a' is the apothem of the polygon and 'p' is the perimeter of the polygon.

From the diagram,

$\sin(60) = \frac{a}{8}$

a=8sin(60)

$a = 4 \sqrt{3}$

$\cos(60) = \frac{l}{8}$

$l = 8 \cos(60)$

$l = 4$

The length of one side of the hexagon is 2×4=8.

The perimeter of the hexagon is

p=6×8=48

The area of the hexagon is

$= \frac{1}{2} \times 4 \sqrt{3} \times 48$

$= 96 \sqrt{3} {cm}^{2}$

Answer 2

Answer:

the correct answer is 96√3 i just took the unit test. have a blessed day :)

Step-by-step explanation: