Answer:
In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven
Step-by-step explanation:
Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.
Using the Pythagoras theorem we can calculate the hypotenuse adjacent as follows.
a²+b²=c²
a²=c²-b²
a²=4²-3²
a²=16-9
a²=7
a=√7
Then Cos ∅= opposite/ adjacent
=√7/4
Then Tan ∅ = opposite/adjacent
=3/√7
In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven.
![x^5-8x^3-9x\\\\[Factor]x(x+3)(x-3)(x^2+1)\\\\[Set all the items equal to 0.]x = 0\\\\x+3=0\\x=-3\\\\x-3=0\\x=3\\\\x^2 +1=0\\x^2=-1\\x=i,-i](https://tex.z-dn.net/?f=x%5E5-8x%5E3-9x%5C%5C%5C%5C%5BFactor%5Dx%28x%2B3%29%28x-3%29%28x%5E2%2B1%29%5C%5C%5C%5C%5BSet%20all%20the%20items%20equal%20to%200.%5Dx%20%3D%200%5C%5C%5C%5Cx%2B3%3D0%5C%5Cx%3D-3%5C%5C%5C%5Cx-3%3D0%5C%5Cx%3D3%5C%5C%5C%5Cx%5E2%20%2B1%3D0%5C%5Cx%5E2%3D-1%5C%5Cx%3Di%2C-i)
The 5 roots are 0, -3, 3, i, and -i.
⭐ Answered by Hyperrspace (Ace) ⭐
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The answer is x=5. I've included the work in the picture attached.
The answer is 838.09528(09528 has a line above it)
Answer:
0.9466 = 94.66% probability that the weight of a randomly selected steer is between 639 and 1420lbs.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the probability that the weight of a randomly selected steer is between 639 and 1420lbs.
This is the pvalue of Z when X = 1420 subtracted by the pvalue of Z when X = 639. So
X = 1420



has a pvalue of 0.9821
X = 639



has a pvalue of 0.0355
0.9821 - 0.0355 = 0.9466
0.9466 = 94.66% probability that the weight of a randomly selected steer is between 639 and 1420lbs.