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3 years ago

Can someone please help me with this?

Mathematics

2 answers:

tamaranim1 [39]3 years ago

6 0

X would be 360 - 90 = 270 degrees Answer

andrezito [222]3 years ago

3 0

90 is the answer to that

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10th grade geometry <br> Select statements that are true about angles on diagram

Goshia [24]

Answer:

B, C

Step-by-step explanation:

The only statements that must be true are ones that describe the markings on the diagram:

NO as an angle bisector

N is the vertex of a pair of congruent angles

_____

The only other fact that must be true is that segments on the left side of the diagram are proportional to those (corresponding) on the right. (This is a property of the angle bisector.) There is nothing that says the sides must be equal, or that the triangle is isosceles.

3 0

2 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

28 + 2A = 5A + 7<br><br> Please explain thank you!

Vinvika [58]

First you need to get x on one side of the equation and to do that subtract 2a from both sides.
28 + 2a = 5a + 7
-2a -2a
28=3a+7

Then we need to get a alone by subtracting 7 on both sides.
28=3a+7
-7 -7
21=3a

Finally divide each side by 3 and you should get a = 7. Hope this helps!

3 0

3 years ago

PLEASE HELP I WILL MARK BRAINLIEST

worty [1.4K]

The answer would be 7 inches i believe?..

6 0

3 years ago

Read 2 more answers

1. The 4th, 5th, and 6th terms of an arithmetic sequence are 19, 23, and 27 respectively. What is the first

babymother [125]

Answer: 7

Step-by-step explanation: The only pattern in this sequence that I can see is addition by 4. Therefore, the 3rd term is 15, the 2nd is 11, the 1st is 7.

Please consider Brainliest.

8 0

1 year ago