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Neko [114]
3 years ago
10

A pyramid has a square base with sides of length s the height of The pyramid is equal to 1/2 Of the length of a side on the base

. Which formula represents the volume of the pyramid?
Mathematics
2 answers:
DENIUS [597]3 years ago
3 0

Answer:

The correct answer is s³/6

Step-by-step explanation:

<u>Points to remember</u>

Volume of pyramid = (a²h)/3

Where a -  side of base

h - height of pyramid

It is given that, a  pyramid has a square base with sides of length s the height of The pyramid is equal to 1/2 Of the length of a side on the base

<u>To find the formula:-</u>

Here side length a = s and

height h = 1/2(s) = s/2

Volume = (a²h)/3

 = (s² * s/2)/3

 = s³/6

The correct answer is s³/6

slamgirl [31]3 years ago
3 0

Answer:

(s^3)/6

Step-by-step explanation:

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Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

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 \to \mu=\frac{\sum xi}{n}

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\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

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In point d:

\to \mu=\frac{\sum xi}{n}

       =20.8375  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

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