I'm so sorry but I can't help you with this problem
<h2>
Answer:</h2><h2>80%.</h2>
Step-by-step explanation:
Answer:
f=70 d=105
a=175 e=180
if not
is this from a textbook
Step-by-step explanation:
Answer:
a. 52%
b. 40%
Step-by-step explanation:
Let A represents the event of raining on Monday and B represents the event of raining in Tuesday,
Then according to the question,
P(A) = 20% = 0.2,
P(B) = 40% = 0.4,
Here, A and B are independent events,
So, P(A∩B) = P(A) × P(B),
⇒ P(A∩B) = 0.2 × 0.4 = 0.08
We know that,
P(A∪B) = P(A) + P(B) - P(A∩B)
a. The probability it rains on Monday or Tuesday, P(A∪B) = 0.2 + 0.4 - 0.08
= 0.52
= 52%
b. The conditional probability it rains on Tuesday given that it rained on Monday,

Answer:
48128m^3
Step-by-step explanation:
Given data
For the building
L=64m
W= 6m
H= 36m
The volume is
V= LWH/3
V=64*64*36/3
V=147456/3
V=49152m^3
For the off-Cut
L=16m
W= 16m
H= 12m
The volume is
V= LWH/3
V=16*16*12/3
V=3072/3
V=1024m^3
Hence the volume of the truncated part/Building
= Volume of building-volume of off-cut
=49152-1024
=48128m^3