The two angles are x and 9x/5
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Let the two angles we require be x and y.
<h3 /><h3>Ratio of both angles</h3>
We have that the ratio of both angles are x:y
Since both angles are in the ratio 5:9, we have that,
x:y = 5:9
⇒ x/y = 5/9
<h3 /><h3>Value of the other angle</h3>
So, we Make y subject of the formula
Multiplying both sides by y, we have
y × x/y = 5/9 × y
x = 5y/9
Multiplying both sides by 9, we have
9 × x = 5y/9 × 9
9x = 5y
Dividing both sides by 5, we have
9x/5 = 5y/5
y = 9x/5
So, the two angles are x and 9x/5
Learn more about angles here:
brainly.com/question/14362353
Let Peter's hit be x and Alice's runs be y.
x = 2(y - 6) . . . (1)
x + y = 18 . . . (2)
Putting (1) into (2) gives,
2y - 12 + y = 18
3y = 18 + 12 = 30
y = 30/3 = 10
x = 2(10 - 6) = 2(4) = 8
Therefore, Peter hit 8 home runs and Alice hit 10 home runs.
Answer:
The sixth number in series is 13.
Step-by-step explanation:
Given series : 3, -6, 12, 4, 20, ?
The pattern followed by the series is:
The first number = 3
Second number = 3 - 9 = - 6
Third number = - 6 + (9 ×2) = -6 + 18 = 12
Fourth number = 12 - 8 = 4
Fifth number = 4 + (8 ×2) = 20
Sixth number = 20 - 7 = 13
Seventh number = 13 + (7 ×2) = 13 + 14 = 27 and so on.
So as per the above pattern, the sixth number in the series is 13.
Answer:
3000 grams
Step-by-step explanation:
convert 3 Kg to G
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>
Step-by-step explanation:
Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.
From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by
=
.
So, the population in the year t can be given by 
Population in the year 2000 =
=
Population in year 2000 = 3,762,979
Let us assume population doubles by year
.



≈
∴ By 2033, the population doubles.