Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
The answer to this question is Z = -40
Answer:
c=-4, d=-6
Step-by-step explanation:
Based on the scenario given, the equation to describe the situation will be: c + 125 + 89 = 500 and 286 cards need to be collected.
Number of cards given by grandfather = 125 cards
Number of cards that will be given by father = 89 cards
Therefore, based on the information given, the equation to describe the situation will be:
c + 125 + 89 = 500
Therefore, we can then use the equation to calculate the number of cards that need to be collected. This will be:
c + 125 + 89 = 500
c + 214 = 500
c = 500 - 214
c = 286
Therefore, the person needs to collect 286 cards.
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