Answer:
C
Step-by-step explanation:
Simply just substitute both x and y in the equation..
Expand and then add
With these given values:
<span> f(0)=4 and f′(x)≤4
</span>
The solution is as follows:
<span>f(0) = 4
f ' (x) ≤ 4 for all x
The Mean Value Theorem says there is a c between 0 and 4 such that f ' (c) = [f(4) - f(0)] / (4 - 0)
But since f ' (x) ≤ 4 for all x, then [f(4) - f(0)] / (4 - 0) ≤ 4
Since f(0) = 4, then [f(4) - 4] / (4 - 0) ≤ 4
Multiplying both sides by 4 you get f(4) - 4 ≤ 16
Adding 4 to both sides you get f(4) ≤ 20
So f(4) ≤ 20
</span>
By examining the solution, it could guide you on answering the problem on your own. Hope that helps
(-2x^2)^3*3x is -24x^7
exponents first
(-2x^2)^3
(-2)^3 x^(2)^3 (when raised to a power multiply the powers on the exponent)
(-2) *(-2) *(-2)*x^(2*3)
-8 x^6
-8 x^6 * 3x
-8*3 * x^6 *x (when multiplying add the exponents)
-24 x^(6+1)
-24 x^7
$6.70
unit rate:
5.96 divided by 4 = 1.49.
so then:
1.49 x 4.5 = 6.70