3. ∠1+∠2=180° and ∠2+∠3=180°
4. they are supplementary
5. ∠1+∠2=180°=∠2+∠3
6. ∠1+∠2=180°=∠2+∠3
∠2 are same in both side so ∠1=180°-∠2 =∠3=180°-∠2
7.
468=40x+18(x-3)
468=40x+18x-54
468=58x-54
522=58x
9=x
I'm not sure if you need to know x at all, if not, the top equation is all you need.
Answer:
2*2*9+4*12*3=36+144=180
Step-by-step explanation:
Since you are subtracting 11 on the side with the variable, you have to add it on the other side. 17+11=28. Then, to solve the problem you are left with, 7c=28. You are multiplying on the side of the variable, so you divide 28 by 7. Your answer to the problem is C=4 i hope this helps
