1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ray Of Light [21]
4 years ago
13

Question 5. I need help please

Mathematics
1 answer:
Nonamiya [84]4 years ago
7 0
The answer would be C. 72
You might be interested in
Need help multiplying -300 to N+M&M=10 for equation (1)​
xz_007 [3.2K]

Answer:

3.5 pounds of nuts; 6.5 pounds of M&Ms

Step-by-step explanation:

Let m represent the number of pounds of M&Ms to use. Then 10-m is the number of pounds of nuts, and the cost of the mix is ...

6·m + 3·(10-m) = 4.95·10 . . . . . cost = cost per pound times pounds

3m +30 = 49.5 . . . . . . simplify

3m = 19.5 . . . . . . . . . . . subtract 30

m = 6.5 . . . . . . . . . . . . . divide by 3

Then 10-m = 10-6.5 = 3.5.

The manager should use 3.5 pounds of nuts and 6.5 pounds of M&Ms in the mix.

7 0
3 years ago
Math Help please!
ivolga24 [154]
<span>I believe you MEANT 8/(x^2-25)+9/(x-5)  Parentheses in this format are important...the way you typed it means (8/x^2)-25+(9/x)-5 which I doubt you mean. Anyway.

If you factor the first denominator you will see that it is equal to (x+5)(x-5). Division by zero has no meaning so x cannot equal -5 or 5.

If we multiply the second fraction by (x+5) we will have a common denominator of (x^2-25) for the entire equation leaving us with:

(8+9x+45)/(x^2-25)

(9x+53)/(x^2-25)

The second problem is worked in exactly the same way, notice that there is no "solution" as there is no equal sign.  This is an "expression" not an "equation".</span>
4 0
3 years ago
Need help please some one
ella [17]

Answer:

gforse

Step-by-step explanation: 660

5 0
3 years ago
Read 2 more answers
(50 POINTS) Subtract. (−8.3x+4)−(3.2x−5)
shusha [124]

Answer:

<h2><em>Hello</em><em>!</em><em>!</em><em>!</em></h2>

Step-by-step explanation:

<em>The</em><em> </em><em>first</em><em> </em><em>step</em><em> </em><em>for</em><em> </em><em>solving</em><em> </em><em>this</em><em> </em><em>expression</em><em> </em><em>is</em><em> </em><em>to</em><em> </em><em>remove</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>set</em><em> </em><em>of</em><em> </em><em>parenthesis</em><em>.</em>

<em>-8</em><em>.</em><em>3</em><em>x</em><em>+</em><em>4</em><em> </em><em>-</em><em> </em><em>(</em><em>3</em><em>.</em><em>2</em><em>x-5</em><em>)</em>

<em>Remember</em><em> </em><em>that</em><em> </em><em>when</em><em> </em><em>there</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>"</em><em>_"</em><em> </em><em>sign</em><em> </em><em>in</em><em> </em><em>front</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>parenthesis</em><em>,</em><em> </em><em>we</em><em> </em><em>must</em><em> </em><em>change</em><em> </em><em>the</em><em> </em><em>sign</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>following</em><em> </em>

<em>-8</em><em>.</em><em>3</em><em>x</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>-</em><em> </em><em>3</em><em>.</em><em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>5</em>

<em>Collect</em><em> </em><em>the</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em><em>with</em><em> </em><em>an</em><em> </em><em>x</em><em> </em><em>variable</em><em>.</em>

<em>-11</em><em>.</em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>4</em><em> </em><em>+</em><em> </em><em>5</em>

<em>Lastly</em><em>,</em><em> </em><em>add</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>to</em><em> </em><em>get</em><em> </em><em>your</em><em> </em><em>final</em><em> </em><em>answer</em>

<em>-11</em><em>.</em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>9</em>

<em>Hope</em><em> </em><em>that</em><em> </em><em>helps</em><em> </em><em>you</em><em> </em><em>dear</em><em>.</em><em>.</em><em>.</em>

<em>Have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>.</em><em>.</em>

<em>Buhbye</em><em>!</em>

7 0
3 years ago
If the sides of a square measure 9.3 units the.find the length of the diagonal
arsen [322]

Answer:

Approximately 13.1521 units.

Step-by-step explanation:

To find the diagonal, we can use the Pythagorean Theorem.

Since the figure is a square, all four sides are equivalent. A square also has four right angles. Therefore, we can use the Pythagorean Theorem to find the diagonal d. Therefore:

a^2+b^2=c^2

Substitute 9.3 for a and b, and let c equal d:

(9.3)^2+(9.3)^2=d^2

Instead of squaring, add the like-terms:

2(9.3)^2=d^2

Take the square root of both sides:

d=\sqrt{2(9.3)^2}

Expand:

d=\sqrt{2}\cdot\sqrt{(9.3)^2}

The right cancels:

d=\sqrt2\cdot(9.3)\\d=9.3\sqrt2\\d\approx13.1521\text{ units}

7 0
3 years ago
Other questions:
  • What factors do you think are involved in determining the pitch of the roof? Explain your reasoning.
    12·1 answer
  • Please help me with my math question! Felisa is creating a scrapbook of her family. A photo of her grandmother measures 3 inches
    8·1 answer
  • Civil society organizations focus efforts on __________.
    11·2 answers
  • Solve for b1 from the formula: A=1/2h(b1+b2)
    13·1 answer
  • Use two unit multipliers to convert 1500 centimeters to feet.<br>thanks :)
    14·2 answers
  • Ten years ago, the population at Lincoln High School was about 2,000 students. Since then, the population has increased by 25%.
    10·1 answer
  • NEED HELP ASAP PLS DUE TODAY !!!
    6·1 answer
  • Write each question as a single logarithm (Picture attached)
    8·1 answer
  • Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an hourly rate of $28. T
    8·1 answer
  • Y= x+2 -1 if<br> a)y&gt;0<br> b)y&lt;0<br> c)y=0
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!