Question

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y)(x,y) point.

Answer 1

Answer:

(8,-3)

Step-by-step explanation:

The given parabola is

$y = - 3 {x}^{2} + 48x - 195$

We factor -3 from the first two terms to get:

$y = - 3( {x}^{2} - 16x) - 195$

Add and subtract the square of half the coefficient of x

$y = - 3( {x}^{2} - 16x + 64) + 3 \times 64- 195$

$y = - 3 {(x - 8)}^{2} + 192 - 195$

We simplify to get:

$y = - 3 {(x - 8)}^{2} - 3$

We compare this to y=a(x-h)²+k,

The vertex is (h,k)=(8,-3)