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zvonat [6]
3 years ago
13

Evaluate 7-5p+3q when p = 1 and q = 7

Mathematics
2 answers:
Llana [10]3 years ago
3 0
You have to replace the p and the q in the expressiogn with each given value like this:
7-5(1)+3(7) = 7-5+21 = 23
777dan777 [17]3 years ago
3 0

Answer:

23

Step-by-step explanation: You have to substitute 1 for p & 7 for q. Use GEMDAS/PEMDAS :D

7 - 5p+ 3q

7 - 5(1) + 3(7)

7 - 5 + 21

7 + 16

= 23


Hope this helps you!!! :)


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9. Solve for x,<br>9x - 25<br>5x + 7<br>N​
kati45 [8]

Answer:

x = 8

Step-by-step explanation:

Simplifying

9x + -25 = 5x + 7

Reorder the terms:

-25 + 9x = 5x + 7

Reorder the terms:

-25 + 9x = 7 + 5x

Solving

-25 + 9x = 7 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

-25 + 9x + -5x = 7 + 5x + -5x

Combine like terms: 9x + -5x = 4x

-25 + 4x = 7 + 5x + -5x

Combine like terms: 5x + -5x = 0

-25 + 4x = 7 + 0

-25 + 4x = 7

Add '25' to each side of the equation.

-25 + 25 + 4x = 7 + 25

Combine like terms: -25 + 25 = 0

0 + 4x = 7 + 25

4x = 7 + 25

Combine like terms: 7 + 25 = 32

4x = 32

Divide each side by '4'.

x = 8

Simplifying

x = 8

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Solving Graphically...<br>PLEASE HELP
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This one's not too difficult, giving Brainliest and 40 points to whoever has the best answer
hjlf

15,2,31,13

Answer:

Solution given:a number that is divisible only by itself and 1 (e.g. 2, 3, 5, 7, 11).

now

all prime numbers are:

15,2,31,13

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