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katrin [286]
3 years ago
14

Find the domain and range of f(x ) = (x^2+2x+1)/(x^2-8x+12)

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0
Nter any function to compute the domain<span> and </span>range<span>. Specify a restriction on the independent variable. Compute </span>domain<span> and </span>range<span> for functions of several variables. ... </span>domain<span> and </span>range<span> of (</span>x^2+1)/(x^4-1) ...domain<span> of </span>f(x,y) = log(1-(x^2+y^2<span>)).</span>find<span> the </span>range<span> of </span>f(x<span>) = </span>x2+2x+1/x2-8x+12<span>. ... Write </span>domain<span> and </span>range<span> of greatest integer function.  hopes this helps u


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Write a rule for the linear function in the table.
Ira Lisetskai [31]

Answer:

f(x) = 4 - x

Step-by-step explanation:

'f(x) = blah-blah' is the same as saying 'y = blah-blah', except it is also telling you that the x-y relationship is a function.

I notice that for each case, x + y = 4, so    y = 4 - x

Or in 'function' terminology,                       f(x) = 4 - x

5 0
3 years ago
Use the recipe to find how much hair conditioner Helena needs to make a half batch and a double batch
Lyrx [107]

Answer:

Helena needs 2 ¹/₂ cups water and 1 ¹/₄ cups vinegar for a half batch. She needs 10 cups of water and 5 cups of vinegar for a double batch.

4 0
4 years ago
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After one day, 1000 copies of a CD are sold. Each of the following days, 100 more copies are sold,
lawyer [7]

Answer:

Equation:

y - 1000 = 100(x - 1)

2900 CDs will be sold after 20 days.

Step-by-step explanation:

See image.

6 0
3 years ago
1 by 6 of a construction work is finished in the first year, 1 by 8 part in the second year and 1 by 12 in the third year how mu
Allisa [31]

Answer:

3/8

Step-by-step explanation:

first year's work is 1/6

second year's work is 1/8

third year's work is 1/12

combining all 3 gives us

1/6 + 1/8 + 1/12

which simplifies to 3/8

3 0
3 years ago
-4x to the power of 2 y × -3xy to the power of 3
denis23 [38]

- 4x^2y * 3xy^3

multiply the numbers : 4*3 = 12

-12x^2xy^3y

apply exponent rule : x^2x = x^2+1 = x^3

-12x^3y^3y

apply exponent rule again : y^3y = y^1+3 = y^4

answer : -12x^3y^4

5 0
3 years ago
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